3 consecutive positive integers : x, x + 1, x + 2
x^2 = x + 2
x^2 - x - 2 = 0
(x + 1)(x - 2) = 0
x + 1 = 0
x = -1....this is an extraneous solution that does not work
x - 2 = 0
x = 2
check...
square of the first = third
x^2 = x + 2
2^2 = 2 + 2
4 = 4 (correct)
so ur 3 integers are 2,3, and 4
<span>3.25 mm = 3.25 cm, 30 cm = 12 inches. So, 12/30 x 3.25 = 1.3</span>
8x + 84 = 500
8x = 416
x = 52
So if he wants to earn more than 500 dollars, he needs to make more than 52 dollars a week.
<span>x^2 + 0x - 1 = 0
x^2 - 1 = 0
This is a difference of two squares which factors into the product of a sum and a difference with the pattern: a^2 - b^2 = (a + b)(a - b).
(x + 1)(x - 1) = 0
x + 1= 0 or x - 1 = 0
x = -1 or x = 1
Answer: There are two real solutions.</span>
