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oee [108]
3 years ago
13

Your international diplomacy trip requires stops in Thailand, Singapore, Hong Kong, Laos, and Bali. How many possible itinerarie

s are there in which the last stop is Thailand?
Mathematics
1 answer:
otez555 [7]3 years ago
7 0

Answer:

24.

Step-by-step explanation:

Given, diplomacy trip requires stops in  Singapore, Hong Kong, Laos, and Bali. So, total stops are 4. This question is about how many permutations are there. By using the permutation method, we can identify how many ways I can stop in Thailand.

(The trip starts from Thailand, so we can exclude Thailand from the stops. )

So, the total way is 4! = 1*2*3*4 = 24.

The answer is 24 ways.

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Anna71 [15]

Answer:

p = (0.5 , 5)

Step-by-step explanation:

D(-6 ,4)    E(7 ,6)

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p = (Dx + Ex)/2 , (Dy + Ey)/2

p = (-6 + 7)/2 , (4 + 6)/2

p = 1/2 , 10/2

p = (0.5 , 5)

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4 years ago
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aleksandrvk [35]

Answer:

1. 2.8    2. 1.24   3. 1.75   4. 2.375

Step-by-step explanation:

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8 0
3 years ago
POINTS!!
masya89 [10]

Answer:

1) Please find the attached drawing of the archway created with MS Excel

2) The y-intercept is (0, 24)

The x-intercepts are (-3, 0), and (8, 0)

3) The width of the archway at its base is 11

The height of the archway at its highest point = 30.25

Step-by-step explanation:

The given function representing the archway is y = -x² + 5·x + 24

1) Please find attached the required drawing of the archway created with MS Excel

2) The y-intercept is given by the point where x = 0

Therefore, we have, the y-value at the y-intercept = -0² + 5×0 + 24 = 24

The y-intercept = (0, 24)

The x-intercept is given by the point where y = 0

Therefore, the x-values at the x-intercept are found using the following equation;

0 = -x² + 5·x + 24

x² - 5·x - 24 = 0

By inspection, we have;

x² - 8·x + 3·x - 24 = 0

x·(x - 8) + 3·(x - 8) = 0

∴ (x + 3) × (x - 8) = 0

Either (x + 3) = 0, and x = -3, or (x - 8) = 0, and x = 8

Therefore, the x-intercepts are (-3, 0), and (8, 0)

3) The width of the archway at its base = The distance between the x-values at the two x-intercepts

∴ The width of the archway at its base = 8 - (-3) = 11

The highest point of the arch is given by the vertex of the parabola, y = a·x² + b·x + c, which has the x-value of the vertex = -b/(2·a)

∴ The x-value of the vertex of the given parabola, y = -x² + 5·x + 24, is x = -5/(2×(-1)) = 2.5

Therefore;

The y-value of the vertex, is y = -(2.5)² + 5×2.5 + 24 = 30.25 = The height of the archway at its highest point

∴ The height of the archway at its highest point = 30.25.

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Step-by-step explanation:

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