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2 years ago

Need help doing this, show steps if you could

Mathematics

1 answer:

Anna71 [15]2 years ago

6 0

Answer:

p = (0.5 , 5)

Step-by-step explanation:

D(-6 ,4) E(7 ,6)

For the line FP to be a median, the point p must have the intermediate value at x and at y between points D and E

p = (Dx + Ex)/2 , (Dy + Ey)/2

p = (-6 + 7)/2 , (4 + 6)/2

p = 1/2 , 10/2

p = (0.5 , 5)

This is because for a medium to be the point p has to be right in the middle of the other 2 vertices

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J={x|x is an integer and x>-1}

Digiron [165]

The sentence reads:
J equals the value of x such that x is an integer AND x is greater than -1.

Translated to English, we can say J is an integer which is zero or positive, or in other words, J is a non-negative integer.

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3 years ago

Helpppppppppppp plzzzzzzzzzzzzzzzzzz!

prisoha [69]

Answer: F=140

Step-by-step explanation:

720=(x-60)+(x-40)+(x-20)+130+120+110

720-130-120-110=3x-120

360=3x-120

360+120=3x

480=3x

480/3=x

160=x

F=160-20

Next problem

102+31+x=180

133+x=180

x=180-133

x=47

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2 years ago

I need to know the improper fractions answers for:

zmey [24]

Answer:

Part 1) $x=\frac{15}{2}\ units$

Part 2) $z=\frac{15\sqrt{3}}{2}\ units$

Part 3) $y= \frac{15\sqrt{3}}{4}\ units$

Part 4) $b= \frac{45}{4}\ units$

Step-by-step explanation:

step 1

Find the value of x

In the large right triangle

$cos(60^o)=\frac{x}{15}$ ----> by CAH (adjacent side divided by the hypotenuse)

Remember that

$cos(60^o)=\frac{1}{2}$

substitute

$\frac{1}{2}=\frac{x}{15}$

solve for x

$x=\frac{15}{2}\ units$ ---> improper fraction

step 2

Find the value of z

In the large right triangle

Applying the Pythagorean Theorem

$15^2=x^2+z^2$

substitute the value of x

$15^2=(\frac{15}{2})^2+z^2$

solve for z

$z^2=15^2-(\frac{15}{2})^2$

$z^2=225-\frac{225}{4}$

$z^2=\frac{675}{4}$

$z=\frac{\sqrt{675}}{2}\ units$

simplify

$z=\frac{15\sqrt{3}}{2}\ units$

step 3

Find the value of y

In the right triangle of the right

$sin(30^o)=\frac{y}{z}$ ---> by SOH (opposite side divided by the hypotenuse)

substitute the given values of y and z

Remember that

$sin(30^o)=\frac{1}{2}$

$\frac{1}{2}=y:\frac{15\sqrt{3}}{2}$

solve for y

$\frac{1}{2}= \frac{2y}{15\sqrt{3}}$

$y= \frac{15\sqrt{3}}{4}\ units$

step 4

Find the value of b

In the right triangle of the right

$cos(30^o)=\frac{b}{z}$ ---> by CAH (adjacent side divided by the hypotenuse)

substitute the given values of y and z

Remember that

$cos(30^o)=\frac{\sqrt{3}}{2}$

$\frac{\sqrt{3}}{2}=b:\frac{15\sqrt{3}}{2}$

solve for y

$\frac{\sqrt{3}}{2}= \frac{2b}{15\sqrt{3}}$

$b= \frac{45}{4}\ units$

7 0

3 years ago

Find the volume of a sphere made by rotating a circle with a radius of 12 inches. Use 3.14 for π and round to nearest whole numb

nydimaria [60]

Volume = 4/3×pi×r^3
= 4/3×3.14×12^3
= 7234.56
~ 7235

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3 years ago

What is the sum of the sequence 46+47+48+49+...+115

nalin [4]

46+47+48+49+115= 305

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3 years ago

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