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Usimov [2.4K]
3 years ago
15

Solve This equation and Show Work 1/2d + 3/8 = -2d

Mathematics
1 answer:
Effectus [21]3 years ago
5 0

½d + 3/8 = -2d

<span>-½d           -½d</span>

<span>3/8          = -2 ½d</span>

<span>/(-2 ½)      /(-2 ½)</span>

<span>3/20        = d </span>

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Graph the line for <br> y+1=−3/5(x−4)<br> on the coordinate plane.
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Please enclose that -3/5 in parentheses:  <span>y+1= (−3/5)(x−4)
</span>
Let's use the intercept method to graph this line.
First, set x = 0 and find y; this y will be the y-coordinate of the vertical intercept:

y+1= (−3/5)(0−4)  =>  y = -1 + 12/5 = -5/5 + 12/5 = 7/5.  Plot (0, 7/5).

Next, set y = 0 and find x; this will give us the coordinate of the horiz. int.:

0+1= (−3/5)(x−4) => -5/3 = x - 4, or x = 4- 5/3, or  x = 7/3.  Plot (7/3, 0).

Now draw a straight line thru these two points.

6 0
3 years ago
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Using the graph, determine the coordinate of the vertex of the parabola.
Sever21 [200]

Answer:

The coordinates for the vertex are ( -6 , 1 )

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RDN’s sales of cable modem in San Mateo, California, for the months of January through April were as follows:January February Ma
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I have no clue?............
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If I fly in a helicopter for 20 minutes at a speed of 240 km per hour, how fast did I go
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Seorang pemilik toko sepatu ingin mengisi tokonya dengan sepatu laki-laki paling sedikit 100 pasang dan sepatu wanita paling sed
taurus [48]

Answer:

<em>The biggest profit that can be obtained by the shop owner= </em>IDR 2,750,000.

Step-by-step explanation:

We need to form a LPP( Linear Programming Problem) for the following problem and solve it to get the maximize the profit.

Let x denote the number of men's shoe and y denote the number of female shoes.

Maximize z= 10000x+5000y----------(1)

             x≥100 ( since a shoe store owner wants to fill his shop with at least    100 pairs of men's shoes )

            y≥150  (at least 150 pairs of women's shoes).

also x+y≤400   (The store can only accommodate 400 pairs of shoes).

         x≤150    (male shoes should not exceed 150 pairs).

⇒         100≤x≤150

Hence the optimal solution of an LPP always lie on the end points.

We have end points as:

(100,300), (150,250), (100,150),(150,150).

by putting these value in equation (1) we see which give the maximum solution.

for (100,300) i.e. x=100 and y=300:   z=2,500,000

for (150,250) i.e. x=150 and y=250:  z=2,750,000

for (100,150) i.e. x=100 and y=150: z=1,750,000

for (150,150) i.e. x=150 and y=150: z=2,250,000

Hence maximum profit is obtained at x=100 and y=300.

i.e. to maximize the profit:

<em>Number of men's shoes to be kept in store=100</em>

<em>and number of women's shoes to be kept in store=300</em>

<em>The biggest profit that can be obtained by the shop owner= </em>IDR 2,750,000.

5 0
4 years ago
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