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timurjin [86]
3 years ago
14

Help me please :)....

Mathematics
1 answer:
den301095 [7]3 years ago
4 0

Answer:

a = 6, b = 12, c = 18, d = 12

Step-by-step explanation:

You might be interested in
Rebecca has 45 coins, all nickels and dimes. The total value of the coins is $3.60. How many
kvv77 [185]

Answer:

Rebecca has 18 nickels and 27 dimes

Step-by-step explanation:

Let x be the number of nickels Rebecca has, then 45-x is the number of dimes she has.

The total value of Rebecca's coins is $3.60.

1 nickel - 5 cents

x nickels - 5x cents

1 dime - 10 cents

45-x dimes - 10(45-x) cents

Total x nickels and 45-x dimes is 5x+10(45-x) cents that is $3.60=360 cents. So,

5x+10(45-x)=360

5x+450-10x=360

5x-10x=360-450

-5x=-90

5x=90

x=18

45-x=45-18=27

4 0
4 years ago
I geometry, you can use deductive rules to ?
omeli [17]

Answer:

In geometry, you can use deductive rules to prove that a given statement or conjecture is true or false using deductive reasoning.

Step-by-step explanation:

You can use deductive rules to prove that a given statement or conjecture is true or false using deductive reasoning.

7 0
3 years ago
Rewrite 7/6 divided by 1/3
Arte-miy333 [17]

Answer:

7/6 * 3/1 =21/6 you just flip the fraction when doing division.

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
The oil prices for 2014, rounded to the nearest dollar, were: 95, 101, 101, 102, 102, 106, 104, 97, 93, 84, 76, 59. what is the
kipiarov [429]
  • Interquartile Range (IQR) = Q_3-Q_1 , with Q_3 as the upper quartile and Q_1 as the lower quartile.

Firstly, rearrange the data so that it's in ascending order: \{59,76,84,93,95,97,101,101,102,102,104,106\}

Next, find the median:

\{59,76,84,93,95,\boxed{97,101,}101,102,102,104,106\}\\\\\frac{97+101}{2}\\\\\frac{198}{2}\\\\99

Now to find the lower quartile, find the "median" of the data set that's to the left of 99:

\{\overbrace{59,76,84,93,95,97}^{\textsf{to the left of the median}},101,101,102,102,104,106\}\\\\\{\overbrace{59,76,\boxed{84,93}95,97}^{\textsf{to the left of the median}},101,101,102,102,104,106\}\\\\\frac{84+93}{2}\\\\\frac{177}{2}\\\\88.5

Now to find the upper quartile, it's the similar process as finding the lower quartile, except that you are finding the "median" of the data set to the right of 99:

\{59,76,84,93,95,97,\overbrace{101,101,102,102,104,106}^{\textsf{to the right of the median}}\}\\\\\{59,76,84,93,95,97,\overbrace{101,101,\boxed{102,102} 104,106}^{\textsf{to the right of the median}}\}\\\\\frac{102+102}{2}\\\\\frac{204}{2}\\\\102

Now that we have the upper and lower quartile, subtract them:

102-88.5=13.5

<u>In short, the IQR of this data set is 13.5.</u>

8 0
3 years ago
5. Find the actual distance between two cities that are 4 3/4 inches apart on a map with a scale of 1 inch per 40 miles
lyudmila [28]

Answer:

190

Step-by-step explanation:

im lazy

6 0
3 years ago
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