UTF-8- is a variable width character encoding capable of encoding all 1,112,064 valid code points in Unicode using one to four 8-bit bytes. The encoding is defined by the Unicode standard. The sac character encoding method was addressed to simplify the symbolism of letter and symbols.As the computers grew in capacity UTF-8 method was implemented to optimize such protocol allowing more characters to be included with an expanded string of possibilities
kung ito ay sa araling panlipunan,
1. Emigrante/Emigrant- mga taong paalis sakanilang bayan upang manirahan sa ibang bansa(umaalis ng bansa).
2. Imigrante/Immigrant- mga taong nagsisimulang itaguyod ang kanilang pamumuhay sa ibang bansa (pumapasom sa ibang bansa).
3. Irregular Immigrants- ay mga mamamayan na nagtungo sa ibang bansa na hindi dokumentado, walang permit para magtrabaho at sinasabing overstaying sa ibang bansa pinuntahan.
4. Temporary Migrant- ang tawag sa mga mamamayan na nagtungo sa ibang bansa na may kaukulang permiso at papeles upang manirahan nang may takdang panahon.
5. Permanent Migrants- ay mga overseas (Filipinos) na ang layunin ay hindi lamang trabaho kundi permanente na paninirahan sa piniling bansa.
6. Flow- tumutukoy sa dami o bilang ng mga nandarayuhang pumapasok sa isang bansa sa isang takdang panahon na kadalasan ay kada taon.
Explanation:
Di ako sure kung yan ang hanap mo or science.
If (sales >= 10000)
commission = 0.2;
Answer:
// here is code in C++
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int n,no_open=0;
cout<<"enter the number of lockers:";
// read the number of lockers
cin>>n;
// initialize all lockers with 0, 0 for locked and 1 for open
int lock[n]={};
// toggle the locks
// in each pass toggle every ith lock
// if open close it and vice versa
for(int i=1;i<=n;i++)
{
for(int a=0;a<n;a++)
{
if((a+1)%i==0)
{
if(lock[a]==0)
lock[a]=1;
else if(lock[a]==1)
lock[a]=0;
}
}
}
cout<<"After last pass status of all locks:"<<endl;
// print the status of all locks
for(int x=0;x<n;x++)
{
if(lock[x]==0)
{
cout<<"lock "<<x+1<<" is close."<<endl;
}
else if(lock[x]==1)
{
cout<<"lock "<<x+1<<" is open."<<endl;
// count the open locks
no_open++;
}
}
// print the open locks
cout<<"total open locks are :"<<no_open<<endl;
return 0;
}
Explanation:
First read the number of lockers from user.Create an array of size n, and make all the locks closed.Then run a for loop to toggle locks.In pass i, toggle every ith lock.If lock is open then close it and vice versa.After the last pass print the status of each lock and print count of open locks.
Output:
enter the number of lockers:9
After last pass status of all locks:
lock 1 is open.
lock 2 is close.
lock 3 is close.
lock 4 is open.
lock 5 is close.
lock 6 is close.
lock 7 is close.
lock 8 is close.
lock 9 is open.
total open locks are :3