Answer:
x+3y-6=0
Step-by-step explanation:
given eqn is y=3x-2 which is 3x-y-2=0
the eqn of line perpendicular to given eqn is -x+3y+k=0
it passes through (6,4)
-6+3*4+k=0
or,. -6+12+k=0
or, k= -6
therefore, the eqn of line perpendicular to given eqn is x+3y-6=0
The answer is that he has a 40% chance
10*100=1000
1000/25=40
Making it a 40% chance
Answer:
10x=1/2(x+3)
Step-by-step explanation:
Hope it helps :)
Brainliest pls? Have a good day/night
Answer:
The answer for (a) is at the picture
(b) The vertex is (-2,7)
(c) Yes the parabola open downward
(d) -(x+2)^2+7 the turning point is at (-2,7) since it is where the group curves
Step-by-step explanation: