V= Area of the circle at the base • height =
Pi•r^2 •h
Answer:
Step-by-step explanation:
Here the region between two curves is rotated about a vertical line.
The functions are
![y = sin^2x, \\y = sin^4x, \\x in [0,[pi]/2].](https://tex.z-dn.net/?f=y%20%3D%20sin%5E2x%2C%20%5C%5Cy%20%3D%20sin%5E4x%2C%20%5C%5Cx%20in%20%5B0%2C%5Bpi%5D%2F2%5D.)
Intersecting points are x=0 and x =pi/2
Since rotated about x = pi/2 we get
using cylindrical shell method
Volume = 
From wolfram alpha we find that
Volume= 
Answer:
<h2>
64 cm²</h2>
Step-by-step explanation:
given:
the scale from a square park to a drawing of the park is 5 m to 1 cm
the actual park has an area of 1,600 m²
find:
what is the area of the drawing of the park
solution:
drawing scale is 5m : 1cm
<u>1,600 m² </u> = <u> 5² m² </u>
x 1² cm²
cross multiply:
5² m² x = 1600 m² (1 cm²)
x =<u> 1600 m² </u>
5² m²
x = 64 cm²
therefore, the area of a square park in the drawing is 64 cm²
Product=multiplication
Sum=addition
Difference=subtraction
Quotient=division
Quantity=parentheses
Answer:
ushsh
Step-by-step explanation:
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