A. Choudhury’s bowling ball factory in Illinois makes bowling balls of adult size and weight only. The standard deviation in the
weight of a bowling ball produced at the factory is known to be 0.12 pounds. Each day for 24 days, the average weight, in pounds, of nine of the bowling balls produced that day has been assessed as follows:
Day Average (LB) Day Average (LB)
1 16.3 13 16.3
2 15.9 14 15.9
3 15.8 15 16.3
4 15.5 16 16.2
5 16.3 17 16.1
6 16.2 18 15.9
7 16.0 19 16.2
8 16.1 20 15.9
9 15.9 21 15.9
10 16.2 22 16.0
11 15.9 23 15.5
12 15.9 24 15.8
Required:
a. Establish a control chart for monitoring the average weights of the bowling balls in which the upper and lower control limits are each two standard deviations from the mean. What are the values of the control limits?
b. If three standard deviations ate used in the chart, how do these values change? Why?
Day Average (LB) Day Average (LB)
1 16.3 13 16.3
2 15.9 14 15.9
3 15.8 15 16.3
4 15.5 16 16.2
5 16.3 17 16.1
6 16.2 18 15.9
7 16.0 19 16.2
8 16.1 20 15.9
9 15.9 21 15.9
10 16.2 22 16.0
11 15.9 23 15.5
12 15.9 24 15.8
Required:
a. Establish a control chart for monitoring the average weights of the bowling balls in which the upper and lower control limits are each two standard deviations from the mean. What are the values of the control limits?
b. If three standard deviations ate used in the chart, how do these values change? Why?
1 answer:
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The volume we're looking for is the volume of both cones in the figure.
The volume of a cone is .
So, .
<u>Cone 1's variables:</u>
r = 2.6
h = 5
<u>Cone 2's variables:</u>
r = 2.6
h = 3
Now we can just plug and chug!
V = c. 56.6 cubic units