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Sunny_sXe [5.5K]
3 years ago
7

Write the point -slope form of the equation of each line given the slope and y-intercept. Slope=(2/3), y-intercept =0

Mathematics
1 answer:
MakcuM [25]3 years ago
6 0

Answer:

\large\boxed{y-0=\dfrac{2}{3}(x-0)\to y=\dfrac{2}{3}x}

Step-by-step explanation:

The point-slope form of ane equation of a line:

y-y_1=m(x-x_1)

<em>m</em><em> - slope</em>

<em>(x₁, y₁)</em><em> - point on a line</em>

<em />

We have:

m=\dfrac{2}{3}

y-intercept is for x = 0.

Therefore, if y-intercept = 0, then we have the point (0, 0).

y-intercept=0\to(0,\ 0)

Substitute:

y-0=\dfrac{2}{3}(x-0)\to y=\dfrac{2}{3}x

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Answer:

Option (4).

Step-by-step explanation:

In the figure attached,

Two right triangles ΔXYZ and ΔTUV have been given,

Given:

1). m∠Y = m∠U = 30°                  

2). m∠Z = m∠V = 60°                  

3). m∠X = m∠T = 90°

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Option (4) is the correct option.

8 0
3 years ago
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1 year ago
How do you calculate the perimeter of a circle
sasho [114]

Answer:

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Step-by-step explanation:

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3 years ago
For what value of k does the equation 6(x + 1) + 2 = 3(k5x + 1) + 3 have no solution?
NARA [144]

Answer:

k = (6/15)

Step-by-step explanation:

The equation is:

6*(x + 1) + 2 = 3*(k*5*x + 1) + 3

To have no solutions, we need to have something like:

x + 7 = x + 4

where we can remove x in both sides and end with

7 = 4

So this equation is false, meaning that there is no value of x such that this equation is true, then the equation has no solutions.

First, let's try to simplify our equation:

6*(x + 1) + 2 = 3*(k*5*x + 1) + 3

6*x + 6 + 2 = 3*k*5*x + 3*1 + 3

6*x + 8 = 15*k*x + 6

if 15*k = 6, then the system clerly has no solution.

then:

k = 6/15

then we get:

6*x + 8 = (6/15)*15*x + 6

6*x + 8 = 6*x + 6

8 = 6

The system has no solutions.

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2 years ago
Such that |x-a|&lt;\varepsilon and $x-b|&lt;\varepsilon. can $a$ be countable? can $a$ be uncountable?
Brrunno [24]
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3 years ago
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