Solving a polynomial inequation
Solving the following inequation:
(x - 8) (x + 1) > 0
We are going to find the sign both parts of the multiplication,
(x - 8) and (x + 1), have when
x < - 8
-8 < x < 1
1 < x
Then we know (x - 8) (x + 1) > 0 whenever (x - 8) (x + 1) is positive
We can see in the figure (x - 8) (x + 1) is positive when x < -8 and x > 1
Then
Answer:B
Answer:
part to whole !
Step-by-step explanation:
24 is the total number of kids in her class, and the 15 is the PART of the Whole number of kids in her class that are girls. hope this helps, please mark me brainliest thanks !
Divide 10 each time.
300/10=30
30/10=3
3/10=0.3
0.3/10=0.03
0.03/10=0.003
etc.
Multiply 80 the way you would 100 to get the answer. 100 times .032 equals 3.2, therefore 80 times .032 equals the answer. (2.56)
