Answer:
0.06
Step-by-step explanation:
The computation of the value of p is shown below;
P in the case (2 points if not fouled) = 0.6
Now Expected points if not fouled is
= 0.6 × 2
= 1.2
Now Expected points from free throw is
0 × (1-p)^2 + 1 × 2p(1-p) + 2 × p^2 = 2p
As we can see that 2p would be lower tha 1.2 in order to make a foul on shooter that represent all values of p<0.06 would be considered to foul in the shooter
Answer:
5.25 miles.
Step-by-step explanation:
What I did was I took 3/4 and made it into its decimal form which is 3/4. I then times it by 7 to get 5.25.
5.25 miles is your answer.
Answer:−
1
2
+
6
4
Step-by-step explanation:−
3
4
(
4
−
2
)
Simplify
1
Combine multiplied terms into a single fraction
−
3
4
(
4
−
2
)
−
3
(
4
−
2
)
4
2
Distribute
Solution
−
1
2
+
6
Answer:
For a circle of radius R, the circumference is:
C = 2*pi*R
where pi = 3.14
And if we have an arc defined by an angle θ, the length of the arc is:
A = (θ/360°)*2*pi*R
Here we can not see the image, then i assume that B is the angle that defines the arc AC.
Now we know that the circumference is 120 in, then:
2*pi*R = 120in
Then the length of the arc is:
A = (θ/360°)*120 in
Then if the angle is 18°, we have:
A = (18°/360)*120 in = 6in
Hi there!
![\large\boxed{(-\infty, \sqrt[3]{-4}) \text{ and } (0, \infty) }](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B%28-%5Cinfty%2C%20%5Csqrt%5B3%5D%7B-4%7D%29%20%5Ctext%7B%20and%20%7D%20%280%2C%20%5Cinfty%29%20%7D)
We can find the values of x for which f(x) is decreasing by finding the derivative of f(x):
Taking the derivative gets:
Find the values for which f'(x) < 0 (less than 0, so f(x) decreasing):
0 = -8/x³ - 2
2 = -8/x³
2x³ = -8
x³ = -4
![x = \sqrt[3]{-4}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5B3%5D%7B-4%7D)
Another critical point is also where the graph has an asymptote (undefined), so at x = 0.
Plug in points into the equation for f'(x) on both sides of each x value to find the intervals for which the graph is less than 0:
f'(1) = -8/1 - 2 = -10 < 0
f'(-1) = -8/(-1) - 2 = 6 > 0
f'(-2) = -8/-8 - 2 = -1 < 0
Thus, the values of x are:
![(-\infty, \sqrt[3]{-4}) \text{ and } (0, \infty)](https://tex.z-dn.net/?f=%28-%5Cinfty%2C%20%5Csqrt%5B3%5D%7B-4%7D%29%20%5Ctext%7B%20and%20%7D%20%280%2C%20%5Cinfty%29)
