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ale4655 [162]
3 years ago
6

Separate the number 41 and the two parts so that the first number is eight more than twice the second number what are the two nu

mbers
Mathematics
1 answer:
vesna_86 [32]3 years ago
7 0

The two numbers are 30 and 11

<em><u>Solution:</u></em>

Given that we have to separate the number 41 into two parts

Let the second number be "x"

<em><u>Given that first number is eight more than twice the second number</u></em>

first number = eight more than twice the second number

first number = 8 + twice the "x"

first number = 8 + 2x

So we can say first number added with second number ends up in 41

first number + second number = 41

8 + 2x + x = 41

8 + 3x = 41

3x = 41 - 8

3x = 33

x = 11

first number = 8 + 2x = 8 + 2(11) = 8 + 22 = 30

Thus the two numbers are 30 and 11

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