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3 years ago

Lmno is a kite find the length of ln

Mathematics

1 answer:

Llana [10]3 years ago

4 0

Where are the numbers so that people can help you

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A person sold 100 shares of stock at a loss of 40%. If the selling price for the 100 shares was $3,000, which of the following c

ivann1987 [24]

A person to the hundred to the store get lost 40% of the selling price of 100

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3 years ago

Twice the greater of two consecutive odd intergers is 13 less than three times the lesser. Find the intergers

erastova [34]

Answer:

$\large\boxed{15, 16}$

Step-by-step explanation:

2 consecutive integers represented as variables:

x, x + 1

Greater one: x + 1

Lesser one: x

Write as an equation

2(Greater) + 13 = 3(Lesser)

Substitute in known values

2(x + 1) + 13 = 3(x)

Multiply

2x + 2 + 13 = 3x

Subtract 2x from both sides of the equation

2 + 13 = x

Add 2 + 13 to simplify

x = 15

Lesser = x = 15

Greater = x + 1 = 15 + 1 = 16

$\large\boxed{15, 16}$

Hope this helps :)

3 0

3 years ago

A vector with magnitude 9 points in a direction 190 degrees counterclockwise from the positive x axis. Write in component form

Over [174]

Answer:

$\vec{v}= \text{ or } \approx$

Step-by-step explanation:

Component form of a vector is given by $\vec{v}=$ , where $i$ represents change in x-value and $j$ represents change in y-value. The magnitude of a vector is correlated the Pythagorean Theorem. For vector $\vec{v}=$ , the magnitude is $||v||=\sqrt{i^2+j^2$ .

190 degrees counterclockwise from the positive x-axis is 10 degrees below the negative x-axis. We can then draw a right triangle 10 degrees below the horizontal with one leg being $i$ , one leg being $j$ , and the hypotenuse of the triangle being the magnitude of the vector, which is given as 9.

In any right triangle, the sine/sin of an angle is equal to its opposite side divided by the hypotenuse, or longest side, of the triangle.

Therefore, we have:

$\sin 10^{\circ}=\frac{j}{9},\\j=9\sin 10^{\circ}$

To find the other leg, $i$ , we can also use basic trigonometry for a right triangle. In right triangles only, the cosine/cos of an angle is equal to its adjacent side divided by the hypotenuse of the triangle. We get:

$\cos 10^{\circ}=\frac{i}{9},\\i=9\cos 10^{\circ}$