Let w represent the width of the rectangle in cm. Then its length in cm is (3w+9). The perimeter is the sum of two lengths and two widths, so is ...
... 418 = 2(w + (3w+9))
... 209 = 4w +9 . . . . . . divide by 2, collect terms
... 200 = 4w . . . . . . . . subtract 9
... 50 = w . . . . . . . . . . divide by 4
... length = 3w+9 = 3·50 +9 = 159
The dimensions of this piece of land are 159 cm by 50 cm.
There is no picture attached to the question??
Answer: the answer is c I believe
Step-by-step explanation:
Answer:
Option A
Step-by-step explanation:
Given that A linear model is given for the data in the table: y=1.25x+2.
Let us write observed values for each x and also the predicted values as per equation.
x 2 3 4 8 10 16 20 24 Total
y((O) 3 4 7 12 16 22 28 30
y(P) 4.5 5.75 7 12 14.5 22 27 32
DEv 1.5 1.75 0 0 1.5 0 1 2 7 75
where y(0) represents observed y or y in the table given
y(P) gives values of y predicted as per the equation 1.25x+2
Dev represents the absolute difference
Hence answer is option
A.7.75