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sleet_krkn [62]
3 years ago
8

Which of the following equations could reprwsent the word problem given

Mathematics
2 answers:
Alisiya [41]3 years ago
7 0
Details? Unfortunately I can’t see what you see
Bas_tet [7]3 years ago
6 0
Please provide details such as the word problem and options. 

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Find a number C such that the polynomial p(x)= -x+4x^2+Cx^3-8x^4
Ksenya-84 [330]

Answer:

C = 2

Step-by-step explanation:

p(x)= -x+4x^2+Cx^3-8x^4 \\  \\  \because \: given \: polynmial \: has \: zero \: at \: \\x =  \frac{1}{4}  \\  \\  \implies \: p\bigg(\frac{1}{4}  \bigg) = 0...(1) \\  \\ plug \: x = \frac{1}{4} \:  in \: p(x) \: we \: find \\  \\ p \bigg(\frac{1}{4}  \bigg)  =  - \frac{1}{4} + 4  {\bigg(\frac{1}{4} \bigg)}^{2}  + c  {\bigg(\frac{1}{4} \bigg)}^{3}  - 8  {\bigg(\frac{1}{4} \bigg)}^{4}  \\  \\ 0 = - \frac{1}{4} + \cancel 4 \times   {\frac{1}{\cancel{16} } }  + c  {\bigg(\frac{1}{64} \bigg)}  - \cancel 8  \times  \frac{1}{\cancel{256} }  \\  \\0 =\cancel{ - \frac{1}{4}} + \cancel  {{\frac{1}{4} }}  + c  {\bigg(\frac{1}{64} \bigg)}  -  \times  \frac{1}{32}  \\  \\0 =  c  {\bigg(\frac{1}{64} \bigg)}  -  \frac{1}{32}  \\  \\c  {\bigg(\frac{1}{64} \bigg)} = \frac{1}{32}   \\  \\ c = \frac{1}{32}   \times 64 \\  \\ c = 2

5 0
3 years ago
Find the common ratio 24,18,37/2,81/8
Vinil7 [7]

Note: The third term of the sequence should be \dfrac{27}{2} instead of \dfrac{37}{2}, otherwise the sequence has no common ratio.

Given:

The given sequence is

24,18,\dfrac{27}{2},\dfrac{81}{8}

To find:

The common ratio of the given sequence.

Solution:

The quotient of each pair of consecutive terms are:

\dfrac{18}{24}=\dfrac{3}{4}

Similarly,

\dfrac{\dfrac{27}{2}}{18}=\dfrac{27}{36}

\dfrac{\dfrac{27}{2}}{18}=\dfrac{3}{4}

And,

\dfrac{\dfrac{81}{8}}{\dfrac{27}{2}}=\dfrac{81}{8}\times \dfrac{2}{27}

\dfrac{\dfrac{81}{8}}{\dfrac{27}{2}}=\dfrac{3}{4}

Therefore, the common ratio of the given sequence is \dfrac{3}{4} or 0.75.

8 0
3 years ago
A rectangle has a width of 12 ft and a length of 4 ft. What is the effect on the perimeter when the dimensions are multiplied by
fiasKO [112]
The original perimeter is 32ft.
The dimensions of the new rectangle are 72 ft wide and 24 ft long.
The new perimeter is 192 ft.
When the dimensions are multiplied by 6, the perimeter also multiplied by 6.
5 0
3 years ago
6 apples 4 bananas 3 carrots cost 2.93$ 4 apples 4 bananas and 2 carrots cost 2.22$ 8 carrots cost 0.88$ how much is each item
GarryVolchara [31]

Answer:

Step-by-step explanation:

carrot = 0.11 $ .ie 0.88/8

3 0
3 years ago
If(√14/√7-2)-(√14/√7+2)=a√7+b√2 find the values of a and b where a and b are rational numbers​
seraphim [82]

Answer:

  • a = 4/3 and b = 0

============================

<h2>Given expression:</h2>

\dfrac{\sqrt{14} }{\sqrt{7}-2} -\dfrac{\sqrt{14} }{\sqrt{7}+2}

<h2>Simplify it in steps:</h2>

<h3>Step 1</h3>

Bring both fractions into common denominator:

\dfrac{\sqrt{14} (\sqrt{7}+2)}{(\sqrt{7}-2)(\sqrt{7}+2)} - \dfrac{\sqrt{14} (\sqrt{7}-2)}{(\sqrt{7}-2)(\sqrt{7}+2)}

<h3>Step 2</h3>

Simplify:

\dfrac{\sqrt{14} ((\sqrt{7}+2) - (\sqrt{7}-2))}{(\sqrt{7}-2)(\sqrt{7}+2)} =

\dfrac{\sqrt{14} (\sqrt{7}+2 - \sqrt{7}+2)}{(\sqrt{7}-2)(\sqrt{7}+2)} =

\dfrac{4\sqrt{14} }{(\sqrt{7}-2)(\sqrt{7}+2)} =

\dfrac{4\sqrt{14} }{(\sqrt{7})^2-2^2} =

\dfrac{4\sqrt{14} }{7-4} =

\dfrac{4}{3}  \sqrt{14} }

<h3>Step 3</h3>

Compare the result with given expression to get:

  • a = 4/3 and b = 0

4 0
2 years ago
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