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sleet_krkn [62]
3 years ago
8

Which of the following equations could reprwsent the word problem given

Mathematics
2 answers:
Alisiya [41]3 years ago
7 0
Details? Unfortunately I can’t see what you see
Bas_tet [7]3 years ago
6 0
Please provide details such as the word problem and options. 

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Let set A = {odd numbers between 0 and 100} and set B = {numbers between 50 and 150 that are evenly divisible by 5}. What is A ∩
fgiga [73]
<span>A = {odd numbers between 0 and 100}
</span><span>A = {1, 3, 5, 7,...., 95, 97, 99}

B = </span><span>{numbers between 50 and 150 that are evenly divisible by 5}
B = {50, 55, 60, 65, ..., 140, 145, 150}

The notation </span><span>A ∩ B means the set of items that are in set A and also in set B. In terms of venn diagrams, it's the overlapping region between circle A and circle B

In this case, the following values are found in both set A and set B
{55, 65, 75, 85, 95}

So that's why 
</span>A ∩ B = <span>{55, 65, 75, 85, 95}
which is the final answer
</span>
6 0
3 years ago
What do you get when you put 1 and 1 together?!!?
chubhunter [2.5K]
Two !!!! ...  unless this is some riddle and there's a huge in depth meaningful answer i'm unaware about o.O
7 0
3 years ago
The two shorter sides of a triangle are 9 and 12. what is a possible length to make length of the third side to make the triangl
Paraphin [41]
The two shorter sides of triangle are 9 and 12. what is a possible length to make length of the third side to make the triangle acute with acuteT
6 0
2 years ago
A simple random sample of size n=14 is obtained from a population with μ=64 and σ=19.
madam [21]

Answer:

a) A. The population must be normally distributed

b) P(X < 68.2) = 0.7967

c) P(X  ≥  65.6) = 0.3745

Step-by-step explanation:

a) The population is normally distributed having a mean (\mu_x) = 64  and a standard deviation (\sigma_x) = \frac{19}{\sqrt{14} }

b) P(X < 68.2)

First me need to calculate the z score (z). This is given by the equation:

z=\frac{x-\mu_x}{\sigma_x} but μ=64 and σ=19 and n=14,  \mu_x=\mu=64 and \sigma_x=\frac{ \sigma}{\sqrt{n} }=\frac{19}{\sqrt{14} }

Therefore: z=\frac{68.2-64}{\frac{19}{\sqrt{14} } }=0.83

From z table, P(X < 68.2) = P(z < 0.83) = 0.7967

P(X < 68.2) = 0.7967

c) P(X  ≥  65.6)

First me need to calculate the z score (z). This is given by the equation:

z=\frac{x-\mu_x}{\sigma_x}

Therefore: z=\frac{65.6-64}{\frac{19}{\sqrt{14} } }=0.32

From z table,  P(X  ≥  65.6) =  P(z  ≥  0.32) = 1 -  P(z  <  0.32) = 1 - 0.6255 = 0.3745

P(X  ≥  65.6) = 0.3745

P(X < 68.2) = 0.7967

5 0
3 years ago
Hi! Answer this please!
Rudiy27
The answer would be b
4 0
2 years ago
Read 2 more answers
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