Find the Center and the radius of the circle
x2 + y2 - 6x + 8y- 7 = 0.
1 answer:
Answer:
C(3,-4), r=4*sqrt(2)
Step-by-step explanation:
C(p, q)
x^2+y^2+dx+ey+f=0
p=-d/2, q=-e/2, r^2=p^2+q^2-f
x^2+y^2 - 6x+8y-7=0
p=-(-6)/2=6/2=3
q=-8/2=-4
r^2=3^2 +(-4)^2+7
r^2=9+16+7
r^2=32
r=sqrt(32)
r=sqrt(16*2)
r=4*sqrt(2)
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