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m_a_m_a [10]
3 years ago
11

Help me please I don't understand how to do it

Mathematics
1 answer:
mr_godi [17]3 years ago
4 0
X^2 + 4x -21
= (x +7)(x - 3)

hope that helps
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|v|>3 solution to the inequality on the number line
Andrew [12]
On a number line, v would be all the numbers to the left of -3 (for example, |-4|=4 which is greater than 3) and all the values to the right of positive 3. Since it can't equal 3, v=-3 and v=3 are not included on the number line.
3 0
3 years ago
can someone please help me out with this problem ? i been trying to do this for like 2 days now and i still don’t get it .. also
kotykmax [81]

Answer:

Step-by-step explanation:

the Pythagorean theorem is

c is the hypotenuse which is the side opposite of the right angle

plug the numbers into the Pythagorean theorem

x^2+(\sqrt{26})^2=13^2

when squaring a square root, just take the number in the radical and get rid of the radical

x^2+26=169

subtract 26 from both sides

x^2=143

find the square root of 143

143 is prime so it can just be written as

x=\sqrt{143}

6 0
3 years ago
How do you translate this sentence into an inequality?
iren [92.7K]
5/8x\leq 15
8 0
3 years ago
Read 2 more answers
How many roots would the quadratic y=x^3+2x^2-12x have?
oksano4ka [1.4K]

Answer:

Hi! The answer to your questions is 3 Roots

Step-by-step explanation:

☆*: .。..。.:*☆☆*: .。..。.:*☆☆*: .。..。.:*☆☆*: .。..。.:*☆

☆Brainliest is greatly appreciated!☆

Hope this helps!!

- Brooklynn Deka

4 0
3 years ago
The expressions a(8<img src="https://tex.z-dn.net/?f=x" id="TexFormula1" title="x" alt="x" align="absmiddle" class="latex-formul
amid [387]

Answer:

The expressions a(8x+7) and 4x + 3.5 are equivalent

Therefore, according to the above problem the equation is :---

a(8x + 7) = (4x + 3.5) \\ 8ax + 7a = 4x + 3.5

By comparing the term, we get

8ax = 4x \\ 8a = 4 \\ a =  \frac{4}{8}  \\ \boxed{a = \frac{1}{2} }

and,

7a = 3.5 \\ a =  \frac{3.5}{7}  \\  \boxed{a =  \frac{1}{2} }

<h3>The value of "a" is <u>1/2</u>.</h3>
6 0
3 years ago
Read 2 more answers
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