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Sav [38]
3 years ago
13

Stronomers measure large distances in light-years. One light-year is the distance that light can travel in one year, or approxim

ately 5,880,000,000,000 miles. Suppose a star is 14.4 light-years from Earth. In scientific notation, how many miles away is it
5.88 x 1013 miles 1.44 x 1012 miles 5.88 x 1012 miles 8.4672 x 1013 miles
Mathematics
1 answer:
Komok [63]3 years ago
4 0
This is one of those problems where you don't actually have to know anything. The only answer that is any combination of the two given numbers is the last one:
.. 8.4672*10¹³ miles

_____
That result is the product of 5.88*10¹² and 14.4.
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3 years ago
Ms. Kincaid keeps a supply of dimes and quarters in her car to pay for highway tolls. A week’s supply of toll coins contains 5 m
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Answer: (A) 10

<u>Step-by-step explanation:</u>

                <u>Value</u>       <u>Quantity</u>     =  <u>TOTAL Value</u>

dimes:        .10            Q + 5        =    .10(Q = 5)

quarters:    .25               Q           =      .25Q


Dimes + Quarters = $4.00

.10(Q + 5) + .25Q = 4.00

.10Q + .50 + .25Q = 4.00

           .50 + .35Q = 4.00

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8 0
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The value of the expression \sqrt{x^2y^3} + 2\sqrt{x^3y^4} + xy\sqrt y is 2xy\sqrt{y} + 2xy^2\sqrt{x}

<h3>How to evaluate the sum?</h3>

The attachment represents the proper format of the question

The summation expression is given as:

\sqrt{x^2y^3} + 2\sqrt{x^3y^4} + xy\sqrt y

Expand the radicands

\sqrt{x^2y^2 * y} + 2\sqrt{x^2y^4* x} + xy\sqrt y

Evaluate the square roots

xy\sqrt{y} + 2xy^2\sqrt{x} + xy\sqrt y

Add the like terms

2xy\sqrt{y} + 2xy^2\sqrt{x}

Hence, the value of the expression \sqrt{x^2y^3} + 2\sqrt{x^3y^4} + xy\sqrt y is 2xy\sqrt{y} + 2xy^2\sqrt{x}

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