Answer: Option A is correct that is ![1 +1+\frac{1}{2} +\frac{1}{6}](https://tex.z-dn.net/?f=1%20%2B1%2B%5Cfrac%7B1%7D%7B2%7D%20%2B%5Cfrac%7B1%7D%7B6%7D)
Explanation:
we will substitute the values of n in given expression
![\sum_{n=1}^{4}\frac{n}{n!}](https://tex.z-dn.net/?f=%5Csum_%7Bn%3D1%7D%5E%7B4%7D%5Cfrac%7Bn%7D%7Bn%21%7D)
when substituting n=1 we get in
=![\frac{1}{1!}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B1%21%7D)
when n=2 we get ![\frac{2}{2!}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B2%21%7D)
when n =3 we get
;3 factorial that is 3! = 3 *2*1 = 6
when n=4 we get
;4! = 4*3*2*1 = 24
Note: factorial means the product of the terms getting multiplied till 1
suppose n! will be equal to n(n-1)(n-2)(n-3).......1
Answer:
$3
if we wanted to find how much 1 bottle would cost we would do 6/6=1 and from that we now know that 1 bottle of water costs $1 so if we times that by 3 to find out how much 3 bottles will cost we get $3.