Answer:
22 mu
Explanation:
Since maximum number of flies are observed with +pb and s++ phenotype, they are the parental combinations.
Minimum number of flies are observed with +p+ and s+b phenotype hence they are the result of double crossover.
Gene order would be +bp and s++ since it is the only case which would lead to production of above mentioned double crossover. Hence gene b is in the middle of genes s and p.
Single cross over between genes s and b will give progeny +++ and sbp.
Map distance between s and b loci = recombination frequency =
(number of recombinants/ total progeny)*100
= [(single cross over between s and b + double crossover)/total progeny]*100
= [(102+106+7+5/1000]*100
=(220/1000)*100
=0.22*100
=22 mu
The correct statement concerning chemical bonds and bonding would be C. A molecule having a covalent bond may be polar or Nonpolar.
i believe its packing of materials
Claim: the mean resting pulse rate for men is less than 72
bpm.
Symbolic form would be: μ < 72
Step 1: null hypothesis : μ > = 7 2 b p m
Step 2: alternative hypothesis: μ < 7 2 b p m
Step 3: the test statistic is z = mean – μ / standard dev/sqrt (n) = -3/4 / 1.7639 = -1.92
Step 4: c v method: since z α = -1.645, the test static is z = -1.92 is less than the CV, we reject null hypothesis
P Value method: area is 0.0274, since the p value is <= α, reject null hypothesis.
Step 5: the sample data support the claim that the mean resting pulse rate for men is less than 72 bpm.
