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Rudiy27
3 years ago
11

Help...... ASAP..........

Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
5 0

Answer:

The area is 150

Step-by-step explanation:

<h2>A=\frac{a b}{2}</h2>

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HELP!!! Due in 10 mins help me pls! WILL GIVE BRAINLIEST!!!
Vadim26 [7]

Answer:

1234567890

Step-by-step explanation:

Each of the digits is divisible by their individual index in the number. Adding a 0 at the ends allows for the number to be divisible by 10 and completes the 10 digit requirement.

3 0
2 years ago
Read 2 more answers
Help help help help what is the answer −5(4x−3)−x+5=190!!!
artcher [175]
X=8.5
190-5=185
185/-5=-37
-37-3=-34
34/4=8.5

8 0
3 years ago
An 11-ft ladder leans against the side of a house. The bottom of the ladder is 9-ft from the side of the house. How high is the
bulgar [2K]

Answer:

6.3 ft.

Step-by-step explanation:

This requires the pythagorean theorem: a^2+b^2=c^2 where "a" and "b" are legs and c is the hypotenuse(longest side of the triangle which is opposite to the 90 degree angle.) If we fill the equation where c is the ladder length(11) and "a" is the distance from the house(), and "b" is the height, 9^2+b^2=11^2 or 81+b^2=121. This is equivalent to b^2=40. b=6.3 when rounded to the nearest tenth.

4 0
3 years ago
HALPPP ILL GIVE BRAINALIST
Anestetic [448]

Answer:

1. 2 1/4

2. 8.25

3. 8 6/8

4. 51.18

5. 56.875

6. $6.22

7. 62.14

Step-by-step explanation:

8 0
3 years ago
Questions 16-17 | Math 1 - 0 points Solve the graph Help needed !!
iris [78.8K]

Answer:

16) The area of the circle is 25.1 units²

17) JKLM is a parallelogram but not a rectangle

Step-by-step explanation:

16) Lets talk about the area of the circle

- To find the area of the circle you must find the length of the radius

- In the problem you have the center of the circle and a point on

 the circle, so you can find the length of the radius by using the

 distance rule

* Lets solve the problem

∵ The center of the circle is (1 , 3)

∵ The point on the circle is (3 , 5)

- Using the rule of the distance between two points

* Lets revise it

- The distance between the two points (x1 , y1) and (x2 , y2) is:

 Distance = √[(x2 - x1)² + (y2 - y1)²]

∴ r = √[(3 - 1)² + (5 - 3)²] = √[4 + 4] = √8 = 2√2 units

∵ The area of the circle = πr²

∴ The area of the circle = π (2√2)² = 8π = 25.1 units²

* The area of the circle is 25.1 units²

17) To prove a quadrilateral is a parallelogram, prove that every

     to sides are parallel or equal or the two diagonal bisect

     each other

* The parallelogram can be rectangle if two adjacent sides are

  perpendicular to each other (measure of angle between them is 90°)

 or its diagonals are equal in length

- The parallel lines have equal slopes, then to prove the

  quadrilateral is a parallelogram, we will find the slopes of

  each opposite sides

* Lets find from the graph the vertices of the quadrilateral

∵ J = (0 ,2) , K (2 , 5) , L (5 , 0) , M (3 , -3)

- The opposite sides are JK , ML and JM , KL

- The slope of any line passing through point (x1 , y1) and (x2 , y2) is

 m = (y2 - y1)/(x2 - x1)

∵ The slop of JK = (5 - 2)/(2 - 0) = 3/2 ⇒ (1)

∵ The slope of LM = (-3 - 0)/(3 - 5)= -3/-2 = 3/2 ⇒ (2)

- From (1) and (2)

∴ JK // LM

∵ The slope of KL = (0 - 5)/(5 - 2) = -5/3 ⇒ (3)

∵ The slope of JM = (-3 - 2)/(3 - 0)= -5/3 ⇒ (4)

- From (3) and (4)

∴ KL // JM

∵ Each two opposite sides are parallel in the quadrilateral JKLM

∴ It is a parallelogram

- The product of the slopes of the perpendicular line is -1

* lets check the slopes of two adjacent sides in the JKLM

∵ The slope of JK = 3/2 and the slope of KL = -5/3

∵ 3/2 × -5/3 = -5/2 ≠ -1

∴ JKLM is a parallelogram but not a rectangle

4 0
3 years ago
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