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yulyashka [42]
3 years ago
14

What would this equal and showing work x+36=4x

Mathematics
2 answers:
Alex3 years ago
5 0
X+36=4x
-x       -x
--------------
36=3x
---   ---
 3     3
12=x
irina1246 [14]3 years ago
4 0
Your equation: x+36=4x

You need to get "x" by itself so minus "x" from each side because if you do one thing on one side, you have to do it on the other side too

x-x+36=4x-x⇒36=3x

Now divide 36 by 3 which is 12


Answer: x=12
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What is the inequality of 6x-4<8?
Kobotan [32]
6x - 4 < 8

Add 4 to both sides:
6x < 12

Divide both sides by 6:
x < 2

Answer: x < 2
7 0
3 years ago
Three girls download a total of 36 songs on their iPods. Jane downloaded twice as many as Inez and since Tracy wanted to have th
lesya692 [45]
J + i + t = 36
j = 2i
t = j + 1.....t = 2i + 1

(2i + 1) + i + (2i) = 36
5i + 1 = 36
5i = 36 - 1
5i = 35
i = 35/5
i = 7 <=== Inez downloaded 7 songs

j = 2i = 2(7) = 14 <==Jane downloaded 14 songs
t = 2i + 1 = 2(7) + 1 = 15 <== Tracy downloaded 15 songs

7 0
3 years ago
#2 only <br> And it's to confusing
ipn [44]
They are easy to compare if they all have the same common denominator, then you can easily order them by the magnitude of the numerators...

85/10, -67/10, -56/10, 82/10  so now they are easy to compare...so

-6.7, -28/5, 8.2, 17/2
5 0
3 years ago
Ok her it is need help
Furkat [3]

Answer:

..........

Step-by-step explanation:

5 0
3 years ago
Show that the relation R consisting of all pairs(x, y)such that x and y are bit strings of length three or more that agree in th
Mice21 [21]

Answer:

See proof below

Step-by-step explanation:

An equivalence relation R satisfies

  • Reflexivity: for all x on the underlying set in which R is defined, (x,x)∈R, or xRx.
  • Symmetry: For all x,y, if xRy then yRx.
  • Transitivity: For all x,y,z, If xRy and yRz then xRz.

Let's check these properties: Let x,y,z be bit strings of length three or more

The first 3 bits of x are, of course, the same 3 bits of x, hence xRx.

If xRy, then then the 1st, 2nd and 3rd bits of x are the 1st, 2nd and 3rd bits of y respectively. Then y agrees with x on its first third bits (by symmetry of equality), hence yRx.

If xRy and yRz, x agrees with y on its first 3 bits and y agrees with z in its first 3 bits. Therefore x agrees with z in its first 3 bits (by transitivity of equality), hence xRz.

5 0
3 years ago
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