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Virty [35]
3 years ago
5

Christopher bought 4 pens that cost the same amount of money and a marker that cost $3. He spent a total of $11. Which statement

correctly describes how to find the cost of each pen arithmetically?
Mathematics
1 answer:
Nikolay [14]3 years ago
8 0
The pens cost $2 each.
2*4+3=11
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Solve for x.
olga nikolaevna [1]

Answer:

\boxed{x=5},x=-9

Step-by-step explanation:

To rid the denominators, multiply both sides by (x-3)(x+1).

We get:

6(x+1)-12(x-3)=(x-3)(x+1)

Simplifying, we have:

6x+6-12x+36=x^2-3x+x-3,\\-6x+42=x^2-2x-3,\\x^2+4x-45=0

Solving, we get:

x^2+4x-45=0,\\(x-5)(x+9)=0,\\x=5,x=-9

Therefore, the solution with the greatest value is x=\boxed{5}

8 0
3 years ago
22. f(x) is stretched horizontally by a factor of 2 and reflected across the x-axis. Which choice shows the correct representati
goblinko [34]

Answer:

A. -f(1/2 x)

Step-by-step explanation:

Reflextion about the x-axis is

f(x) -> -f(x)

and horizontal dilation is

f(x) -> f(-x/b) where b is the factor of dilation.

so the proper answwer is

A. -f(1/2 x)

6 0
3 years ago
What is the product? StartFraction 3 k Over k + 1 EndFraction times StartFraction k squared minus 1 Over 3 k cubed EndFraction S
Nana76 [90]

Answer:

StartFraction negative 1 Over k cubed EndFraction

Step-by-step explanation:

3k / (k + 1) × (k²- 1) / 3k³

= 3k(k² - 1) / (k + 1)(3k³)

= 3k³ - 3k / 3k⁴ + 3k³

= -3k / 3k⁴

= -1/k³

StartFraction k + 1 Over k squared EndFraction

(k + 1) / k²

StartFraction k minus 1 Over k squared EndFraction

(k - 1)/k²

StartFraction negative 1 Over k cubed EndFraction

= -1/k³

StartFraction 1 Over k EndFraction

= 1/k

4 0
2 years ago
What is the slope of line on the graph help pwease
Rus_ich [418]

Answer: is where that one dot is at home n the y-axis

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
When the sum of twice a number and 4 is tripled the result is 72?
mafiozo [28]
The unknown value can be called x.
3(2x +4) = 72
6x +12 = 72
72 - 12 = 6x
6x = 60
x = 6x / 6 
x = 10

Hope This Helps You!
<span>Good Luck Studying :)</span>
7 0
3 years ago
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