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Arisa [49]
3 years ago
9

I will give brainliest!!!

Mathematics
1 answer:
olasank [31]3 years ago
5 0

Answer:

the answer is that any number of y is a positive

Step-by-step explanation:

look very closely and you will see what I was just talking about

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Solve using number line (-10)+6<br> ​
Archy [21]

Answer:

       

Step-by-step explanation:

6 0
3 years ago
ILL BRAINLIEST YOU IF YOU GET IT RIGHT PLEASE HELP
soldi70 [24.7K]
The triangle inequality states that in a triangle, any two of the side lengths must add up to a length that is greater than the third. That is, if you have a triangle with sides a, b, and c, then a+b>c, a+c>b, and b+c>a.

In this case, we are given two lengths of a triangle. Let's call those two values a and b, where a>b.

Then we have that c
Now we can also use another inequality, a
Now we can apply these limits to all the individual questions.

1) 13 - 10 < c < 13 + 10. This simplifies down to 3 < c < 23

2) 12 - 5 < c < 12 + 5. This simplifies down to 7 < c < 17

3) 11 - 4 < c < 11 + 4. This simplifies down to 7 < c < 15

Hope it help!
7 0
3 years ago
A reflection of shape I across the y-axis, followed by a ( )
grandymaker [24]

Answer:

180 degrees clockwise for fir part and sec i think is counterclockwise of 90 degreees

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Find equations of both the tangent lines to the ellipse x^2 + 4y^2 = 36 that pass through the point (12, 3).y = (smaller slope)y
Bingel [31]

Answer:

x+y=15

Step-by-step explanation:

Given equation of x^2+4y^2=36

Differentiating both side 2x+8y\frac{dy}{dx}=0

\frac{dy}{dx}=\frac{-x}{4y}

It passes through the point (12,3) so

\frac{dy}{dx}=\frac{-12}{4\times 3}=1

So equation of tangent passing through (12,3) is

y-12=-1(x-3) as y-y_1=-m(x-x_1)

So x+y =15 will be the equation of tangent which passes though the point (12,3)

5 0
3 years ago
Let P (n) be the statement that 12 + 22 + · · · + n2 = n(n + 1)(2n + 1)/6 for the positive integer n. a) What is the statement P
andriy [413]

Answer:

Please see attachment

Step-by-step explanation:

Please see attachment

4 0
3 years ago
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