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WARRIOR [948]
3 years ago
13

A line passes through (−1, 7) and (2, 10).

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
7 0
The slope m of a line through points A(x_1, y_1) and B(x_2, y_2)  is given by :<span>

\displaystyle{m = \frac{y_2-y_1}{x_2-x_1}&#10;



Thus, the slope of the line passing through points </span><span>(−1, 7) and (2, 10) is 

</span>\displaystyle{m= \frac{10-7}{2-(-1)}= \frac{3}{3}=1
<span>

The equation of a line with slope m passing through a point P(a, b) is given by
                                        (y-b)=m(x-a).


We can consider any of the points (-1, 7), or (2, 10). Let's choose (2, 10):

                                        y-10=1(x-2)
                                        y-10=x-2
                                           y-x=-2+10
                                           y-x=8
                                       

  Answer: </span><span>C. −x+y=8</span>
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Step-by-step explanation:

A composite function can be written as g(h(x)), where h and g are basic functions.

For the function f(x)=3(4x^2+8)^5.

The inner function is the part we evaluate first. Frequently, we can identify the correct expression because it will appear within a grouping symbol one or more times in our composed function.

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\frac{d}{dx}[f(g(x))]=f'(g(x))g'(x)

It tells us how to differentiate composite functions.

The function f(x)=3(4x^2+8)^5 is the composition, g(h(x)), of

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The derivative of this is computed as

\frac{d}{dx}\left(3\left(4x^2+8\right)^5\right)=3\frac{d}{dx}\left(\left(4x^2+8\right)^5\right)\\\\\mathrm{Apply\:the\:chain\:rule}:\quad \frac{df\left(u\right)}{dx}=\frac{df}{du}\cdot \frac{du}{dx}\\f=u^5,\:\:u=\left(4x^2+8\right)\\\\3\frac{d}{du}\left(u^5\right)\frac{d}{dx}\left(4x^2+8\right)\\\\3\cdot \:5\left(4x^2+8\right)^4\cdot \:8x\\\\120x\left(4x^2+8\right)^4

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