All categories

2 years ago

BRAINLIESTT ASAP! PLEASE HELP ME :)

Mathematics

1 answer:

sukhopar [10]2 years ago

6 0

Answer: A) none of the equations are identities

==========================================

Part 1

Plug in theta = 0

sin(theta+pi/2) - cos(theta+pi/6) = 2*cos(theta) - sin(theta)

sin(0+pi/2) - cos(0+pi/6) = 2*cos(0) - sin(0)

1 - sqrt(3)/2 = 2*1 - 0

0.13 = 2

which is a false equation

So we do not have an identity in equation 1.

-------------------------------------------

Part 2

Plug in theta = 0

sin(theta+pi/6) + cos(theta+pi/3) = (sqrt(2)/3)*sin(theta) + 2*cos(theta)

sin(0+pi/6) + cos(0+pi/3) = (sqrt(2)/3)*sin(0) + 2*cos(0)

1/2 + 1/2 = 0 + 2

1 = 2

which is also false

This is not an identity either.

You might be interested in

Please Answer its timed The dimensions of a rectangle are represented by the functions shown. g(x)+3x-4 f(x)=2x-9 Which function

Alenkasestr [34]

Answer:

$\boxed{6x^2-35x+36}$

Step-by-step explanation:

The dimensions of the rectangle are represented by functions:

$g(x)=3x-4 \\f(x)=2x-9$

The area is length × width of a rectangle.

$length \times width$

$(3x-4)(2x-9)$

Expand brackets and solve.

$6x^2-27x-8x+36$

$6x^2-35x+36$

5 0

3 years ago

Read 2 more answers

If a•b=b, what must the value of a be?

Mila [183]

Answer: I think f

Step-by-step explanation:

8 0

3 years ago

For the inverse variation equation xy = k, what is the constant of variation, k, when x = 7 and y = 3? three-sevenths seven-thir

vova2212 [387]

The value of the constant k when the value of x and y is 7 and 3 respectively in the equation xy=k is 21.

<h3>What is an equation?</h3>

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

The value of the constant k when the value of x and y is 7 and 3 respectively in the equation xy=k can be written as,

$xy=k\\\\(7) \times (3 ) =k\\\\k= 21$

Hence, the value of the constant k when the value of x and y is 7 and 3 respectively in the equation xy=k is 21.

Learn more about Equation:

brainly.com/question/2263981

4 0

1 year ago

In 5 - 7 complete sentences, answer all of the following question. •Use this image to respond to the following prompt: •Is the s

kaheart [24]

Answer:

positive slope

(0,3)

slope = 2

Step-by-step explanation:

Slope of the given line is positive

If the line is sloping upward from left to right, so the slope is positive (+).

or if the angle made by the line to the x axis is < 90 it's slope is positive.

y-intercept of the line is (0,3)
The y intercept is the point where the line crosses the y axis. At this point x = 0.
slope of the line is 2

slope = (y2 - y1) / (x2 - x1)

lines passing through points (1,5) (0,3)

slope = (3 - 5) / (0 - 1)

= -2 / -1 = 2

7 0

3 years ago

Read 2 more answers

Solve the system of equations by finding the reduced row-echelon form of the augmented matrix for the system of equations.

Anuta_ua [19.1K]

Answer:

Step-by-step explanation:

First, we can transform this into a matrix. The x coefficients will be the first ones for each row, the y coefficients the second column, etc.

$\left[\begin{array}{cccc}1&-2&3&-2\\6&2&2&-48\\1&4&3&-38\end{array}\right]$

Next, we can define a reduced row echelon form matrix as follows:

With the leading entry being the first non zero number in the first row, the leading entry in each row must be 1. Next, there must only be 0s above and below the leading entry. After that, the leading entry of a row must be to the left of the leading entry of the next row. Finally, rows with all zeros should be at the bottom of the matrix.

Because there are 3 rows and we want to solve for 3 variables, making the desired matrix of form

$\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]$ for the first three rows and columns. This would make the equation translate to

x= something

y= something

z = something, making it easy to solve for x, y, and z.

Going back to our matrix,

$\left[\begin{array}{cccc}1&-2&3&-2\\6&2&2&-48\\1&4&3&-38\end{array}\right]$ ,

we can start by removing the nonzero values from the first column for rows 2 and 3 to reach the first column of the desired matrix. We can do this by multiplying the first row by -6 and adding it to the second row, as well as multiplying the first row by -1 and adding it to the third row. This results in

$\left[\begin{array}{cccc}1&-2&3&-2\\0&14&-16&-36\\0&6&0&-36\end{array}\right]$

as our matrix. * Next, we can reach the second column of our desired matrix by first multiplying the second row by (2/14) and adding it to the first row as well as multiplying the second row by (-6/14) and adding it to the third row. This eliminates the nonzero values from all rows in the second column except for the second row. This results in

$\left[\begin{array}{cccc}1&0&10/14&-100/14\\0&14&-16&-36\\0&0&96/14&-288/14\end{array}\right]$

After that, to reach the desired second column, we can divide the second row by 14, resulting in

$\left[\begin{array}{cccc}1&0&10/14&-100/14\\0&1&-16/14&-36/14\\0&0&96/14&-288/14\end{array}\right]$

Finally, to remove the zeros from all rows in the third column outside of the third row, we can multiply the third row by (16/96) and adding it to the second row as well as multiplying the third row by (-10/96) and adding it to the first row. This results in

$\left[\begin{array}{cccc}1&0&0&-5\\0&1&0&-6\\0&0&96/14&-288/14\end{array}\right]$

We can then divide the third row by -96/14 to reach the desired third column, making the reduced row echelon form of the matrix

$\left[\begin{array}{cccc}1&0&0&-5\\0&1&0&-6\\0&0&1&-3\end{array}\right]$

Therefore,

x=-5

y=-6

z=-3

* we could also switch the second and third rows here to make the process a little simpler

3 0

3 years ago