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Stella [2.4K]
3 years ago
7

When graphing how do you solve y=x+3

Mathematics
1 answer:
AysviL [449]3 years ago
7 0
One point would be (0, 0). Then (1, 3), (2, 6), and so on.
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Write the equation in slope-intercept form that contains the following point and is perpendicular to the given line
Len [333]

Answer:

y = 1/4 x -3

Step-by-step explanation:

y = -4x + 3;

the slope of this equation is -4

we want the slope perpendicular to this

take the negative reciprocal

- (-1/4) = 1/4

so the slope of our line will be 1/4

we have the slope and a point so we can use point slope form

y-y1 = m (x-x1)

y--2 = 1/4(x-4)

y+2 = 1/4 (x-4)

we need to change it to slope intercept form (y=mx+b)

distribute

y+2 = 1/4 x -1/4*4

y+2 = 1/4x -1

subtract 2 from each side

y +2-2 = 1/4 x -1-2

y = 1/4 x -3

the slope is 1/4 and the y intercept is -3

8 0
4 years ago
The first step in the process for factoring the trinomial x^2-3x-40 is to
jenyasd209 [6]

(x-8)(x+5)

First thing you do is put the X's into the parentheticals because it is x^2 meaning there are 2 factors with x's. Then, you wonder what factors of -40 could add to get -3. In this case, they are -8 and 5. -8 times 5 is -40 and -8 +5 is -3. Then, you just add -8 and 5 beside the x's in the parentheticals.

5 0
3 years ago
Read 2 more answers
How do I solve this? Step by step
shutvik [7]

Answer:

24.

Step-by-step explanation:

Substitute each instance of x with a 3.

That leaves us with 3^2 + 3x - 5 + 3^2 - 3x + 11.

Combine like terms.

2(3^2) + 6.

Simplify.

2(9) + 6

18 + 6

24.

8 0
3 years ago
Read 2 more answers
Hello pls help I'm dumb thx it's pre calc
Bumek [7]
(f-g)(x)=f(x)-g(x)=
\frac{2x+6}{3x}-\frac{\sqrt{x}-8}{3x}=
\frac{2x+6-(\sqrt{x}-8)}{3x}=
\frac{2x+6-\sqrt{x}+8}{3x}=
\frac{2x-\sqrt{x}+14}{3x}
answer is A
3 0
4 years ago
An employer has a staff of eighty actuaries, ten of whom are student actuaries. A student actuary is allowed a total of ten week
sergiy2304 [10]

Answer:

0.1111

Step-by-step explanation:

From the given information;

Number of staffs in the actuary = 80

Out of the 80, 10 are students.

i.e.

P(student actuary) = 10/80 = 0.125

number of weeks in a year = 52

off time per year = 10/52 = 0.1923

P(at work || student actuary) = (50 -10/52)

= 42/52

= 0.8077

P(non student actuary) = (80 -10)/80

= 70 / 80

= 0.875

For a non-student, they are only eligible to 4 weeks off in a year

i.e.

P(at work | non student) = (52-4)/52

= 48/52

= 0.9231

∴

P(at work) = P(student actuary) × P(at work || student actuary) + P(non student actuary) × P(at work || non studnet actuary)

P(at work) =  (0.125 × 0.8077) + ( 0.875 × 0.9231)

P(at work) = 0.1009625 + 0.8077125

P(at work) = 0.90868

Finally, the P(he is a student) = (P(student actuary) × P(at work || student actuary) ) ÷ P(at work)

P(he is a student) = (0.125 × 0.8077) ÷ 0.90868

P(he is a student) = 0.1009625 ÷ 0.90868

P(he is a student) = 0.1111

5 0
3 years ago
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