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Marizza181 [45]
3 years ago
6

Health club A charges $60 yearly enrollment fee and $2 per visit. Health club B charges $20 yearly enrollment fee and &4 per

visit. What is the number of visit at which both clubs cost the same?
Mathematics
1 answer:
atroni [7]3 years ago
7 0

Answer:

  20 visits

Step-by-step explanation:

The club that charges $40 more for enrollment charges $2 less per visit. The savings on visits is equal to the extra enrollment charge when the number of visits is 40/2 = 20.

For 20 visits, the cost at both clubs is the same.

__

If you let v represent the number of visits, ...

  A = 60 +2v . . . . cost at club A

  B = 20 +4v . . . . cost at club B

  A = B   ⇒   60 +2v = 20 +4v . . . . . . costs are the same for "v" visits

  40 = 2v . . . . . . . subtract 20+2v from both sides

  40/2 = v = 20 . . . . . . same as "word solution" above

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Answer:

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Step-by-step explanation:

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3 years ago
HELP MEEEEEEEEEE Package A contains 3 birthday cards and 2 thank-you notes and costs $9.60. Package B contains 8 birthday cards
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Answer:

Each birthday card costs $2.2 ⇒ answer c

Step-by-step explanation:

* Lets explain how to solve the problem

- Package A contains 3 birthday cards and 2 thank-you notes

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- It costs $26.60

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* Lets change these information to two equations

∵ x represents the cost of each birthday cards

∵ y represents the cost of each thank-you notes

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∵ Bag B contains 8 birthday cards and 6 thank-you notes

∵ Bag B costs $26.60

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∴ The cost of each birthday card is $2.2

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Answer:

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Step-by-step explanation:

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