Ask question

Ask question

All categories

Marizza181 [45]

3 years ago

6

Health club A charges $60 yearly enrollment fee and $2 per visit. Health club B charges $20 yearly enrollment fee and &4 per

visit. What is the number of visit at which both clubs cost the same?

1 answer:

atroni [7]3 years ago

7 0

Answer:

20 visits

Step-by-step explanation:

The club that charges $40 more for enrollment charges $2 less per visit. The savings on visits is equal to the extra enrollment charge when the number of visits is 40/2 = 20.

For 20 visits, the cost at both clubs is the same.

__

If you let v represent the number of visits, ...

A = 60 +2v . . . . cost at club A

B = 20 +4v . . . . cost at club B

A = B ⇒ 60 +2v = 20 +4v . . . . . . costs are the same for "v" visits

40 = 2v . . . . . . . subtract 20+2v from both sides

40/2 = v = 20 . . . . . . same as "word solution" above

You might be interested in

What is the sum of all possible values of y if x is a positive integer, xy > 0, and 6x+2y=25?

SIZIF [17.4K]

Option E

The sum of all possible values of y is 20

<em><u>Solution:</u></em>

Given that,

6x + 2y = 25

Where, xy > 0

We have to find the sum of all possible values of y if x is a positive integer

We can use values of x = 1, 2, 3, 4

For x = 5 and above, y will be negative

<em><u>Substitute x = 1 in given equation</u></em>

6(1) + 2y = 25

6 + 2y = 25

2y = 25 - 6

2y = 19

Divide both the sides of equation by 2

$y = \frac{19}{2}$

<em><u>Substitute x = 2 in given equation</u></em>

6(2) + 2y = 25

2y = 25 - 12

2y = 13

Divide both the sides of equation by 2

$y = \frac{13}{2}$

<em><u>Substitute x = 3 in given equation</u></em>

6(3) + 2y = 25

2y = 25 - 18

2y = 7

Divide both the sides of equation by 2

$y = \frac{7}{2}$

<u><em>Substitute x = 4 in given equation</em></u>

6(4) + 2y = 25

24 + 2y = 25

2y = 25 - 24

2y = 1

Divide both the sides of equation by 2

$y = \frac{1}{2}$

<u><em>Now add all the values of "y"</em></u>

$\text{Sum of possible values of y } = \frac{19}{2} + \frac{13}{2} + \frac{7}{2} + \frac{1}{2}\\\\\text{Sum of possible values of y } = \frac{19+13+7+1}{2}\\\\\text{Sum of possible values of y } = \frac{40}{2}=20$

Thus sum of all possible values of y is 20

3 0

3 years ago

a construction worker has a ladder against the side of a building. the building is 10 feet tall, and the ladder is 15 feet long.

AveGali [126]

Answer:

5

Step-by-step explanation:

4 0

3 years ago

Monthly, Juan's net earnings are $6,000, and expenses are $5,000. If Juan saves the difference, how much will Juan have saved af

lapo4ka [179]

Answer:

$72,000

Step-by-step explanation:

6000-5000=1000

1000x6 =6000

6000x12=72,000

3 0

3 years ago

Galvin is graduating from college in eighteen months, but he will need a loan in the amount of $9,875 for his last three semeste

just olya [345]

$11,657

I hope this helps

5 0

3 years ago

Read 2 more answers

Choose the solution(s) of the following system of equations x2 + y2 = 6 x2 – y = 6

ElenaW [278]

<h2>Answer</h2>

$x=\sqrt{6}, y=0\\ x=-\sqrt{6} , y=0\\x=\sqrt{5} , y=-1\\x=-\sqrt{5} , y=-1$

Or as ordered pairs: $(\sqrt{6} ,0),(-\sqrt{6} ,0),(\sqrt{5} ,-1),(-\sqrt{5} ,-1)$

<h2>Explanation</h2>

Lets solve our system of equations step by step

$x^2+y^2=6$ equation (1)

$x^2-y=6$ equation (2)

1. Solve for $x^2$ in equation (2)

$x^2-y=6$

$x^2=6+y$ equation (3)

2. Replace equation (3) in equation (1) and solve for $y$

$x^2+y^2=6$

$6+y+y^2=6$

$y^2+y=0$

$y(y+1)=0$

$y=0$ or $y=-1$

3. Replace the values of $y$ in equation (3) and solve for $x$

- For $y=0$

$x^2=6+y$

$x^2=6$

$x=\sqrt{6}$ or $x=-\sqrt{6}$

- For $y=-1$

$x^2=6+y$

$x^2=6-1$

$x^2=5$

$x=\sqrt{5}$ or $x=-\sqrt{5}$

So, the solutions of our system of equation are:

$x=\sqrt{6}, y=0\\ x=-\sqrt{6} , y=0\\x=\sqrt{5} , y=-1\\x=-\sqrt{5} , y=-1$

6 0

3 years ago

Read 2 more answers