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2 years ago

Rectangle EFGH is similar to rectangle JKLM. Which proportion can be used to

Mathematics

1 answer:

Dominik [7]2 years ago

6 0

*See attached picture for the diagrams being referred to

Answer:

C. ⁵/12= ²/x

Step-by-step Explanation:

Given that rectangle EFGH is similar to rectangle JKLM, it means the corresponding sides of both rectangles are similar, and as such the ratios if the corresponding sides of rectangle EFGH and rectangle JKLM would be equal.

Thus, EF/JK = FG/KL

Since, EF = 5; JK = 12; FG = 2; and KL= x, therefore, the proportion to use in finding x would be:

⁵/12= ²/x

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HELP PLEASE, Domain and range problem

pentagon [3]

Answer:

Range is number of copies produced and set of values is; 1 ≤ N ≤ 200

Domain; Cost of publishing book in dollars; set of values are; $710 ≤ N ≤ $2700

Step-by-step explanation:

Range is a set of all the possible output values in a function while domain is the set of all possible input values.

Now, the function is given as;

C = 10N + 700

Where;

C is the cost of publishing the book in dollars

N is the number of copies of books produced

Thus, the domain will be a set of N values while Range will be a set of C values.

We are told that the first printing can produce up to 200 copies of the book.

That means a maximum of 200 books and a minimum of 1.

Thus;

Range is; 1 ≤ N ≤ 200

Maximum possible cost of the 200 books is;

C = 10(200) + 700

C = $2700

Minimum cost which will be for 1 book will be;

C = 10(1) + 700

C = $710

Thus,domain is;

$710 ≤ N ≤ $2700

6 0

2 years ago

Write an equation parallel to. Y= -5x 3 and passing through the point (3,13)

vovikov84 [41]

Y = -5x + 28
will be parallel to your equation because it has the same coefficient but will also pass through (3, 13)

3 0

3 years ago

Describe the transformation in the figure below

Keith_Richards [23]

Answer:

A) Reflection.

Step-by-step explanation:

From the figure shown, we can see that the blue triangle is flipped about the x-axis to form the red triangle.

When an object is flipped about a line, then this transformation is called reflection about that line.

Thus, we can say that reflection is taking place in the figure shown in which the x-axis is acting like a mirror. The blue triangle is the pre-image and the red triangle is the image after reflection.

The reflection about x-axis is given by:

$Pre-image(x,y)\rightarrow Image(x,-y)$