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Nikitich [7]
2 years ago
12

Rectangle EFGH is similar to rectangle JKLM. Which proportion can be used to

Mathematics
1 answer:
Dominik [7]2 years ago
6 0

*See attached picture for the diagrams being referred to

Answer:

C. ⁵/12= ²/x

Step-by-step Explanation:

Given that rectangle EFGH is similar to rectangle JKLM, it means the corresponding sides of both rectangles are similar, and as such the ratios if the corresponding sides of rectangle EFGH and rectangle JKLM would be equal.

Thus, EF/JK = FG/KL

Since, EF = 5; JK = 12; FG = 2; and KL= x, therefore, the proportion to use in finding x would be:

⁵/12= ²/x

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-20a divided by 12b would be -1.6
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Please help with question C
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Answer:

55% percentage mark up

Step-by-step explanation:

Formula = Gross profit /  Cost of item  * 100    First we find the Cost of item = 39.99 / 06 = 66.65 as 66.65 * 0.60 = 39.99  then we find the Gross profit 66.65 - 29.99 = 36.66 then plug into the formula  36.66/66.65 * 100 =55.0037509% = 55%

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Beakers X and Y contain some water. If 50 ml of water is transferred from Beaker X
eduard

Answer:

140 ml

Step-by-step explanation:

Let x be the amount of water in Beaker X and y be the amount of water in Beaker Y.

<u>Then we get following equations:</u>

<u>First part</u>

  • x - 50 = 3/7(y + 50)
  • 7x -350 = 3y + 150
  • 7x = 3y + 500

<u>Second part</u>

  • x + 100 = 4(y - 100)
  • x + 100 = 4y - 400
  • x = 4y - 500

<u>Substitute x in first equation:</u>

  • 7(4y - 500) = 3y + 500
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<u>Then finding x:</u>

  • x = 4*160 - 500
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Initial amount of water in Beaker X is 140 ml, in Beaker Y is 160 ml

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3 years ago
Given that f(x)=x^2-3x-54 and g(x)=x+6, find (f•g)(x) and express the result in standard form
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Answer:

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Step-by-step explanation:

I hope it help

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Answer:

Part A

The rotation of the point (x, y) 180° about the origin gives the point (-x, -y)

Therefore, we have the points, ΔLMN, L(1, 1), and M(2, 2), and N(3, 3)

The coordinates of the vertices of the image, ΔL'M'N' are L'(-1, -1), and M'(-2, -2), and N'(-3, -3)

Please find attached the graph of triangle ΔLMN and ΔL'M'N'

Part B

The lines drawn through L and L' and through M and M' are colinear

Part C

A line is defined by two points, such as <em>L </em>and <em>M.</em> Rotation of a line through 180° about the origin will give an image location on the same path as the extension of the original line.

The third point, <em>N</em>, however, defines a plane, and the rotation of a plane by 180° will give an image which is turned upside down with regards to the preimage

Therefore, a trough in the preimage becomes a peak in the image and the lines drawn through N and N' crosses the colinear lines drawn throgh M and M' and L and L'

Step-by-step explanation:

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