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sdas [7]
3 years ago
8

Beakers X and Y contain some water. If 50 ml of water is transferred from Beaker X

Mathematics
1 answer:
eduard3 years ago
4 0

Answer:

140 ml

Step-by-step explanation:

Let x be the amount of water in Beaker X and y be the amount of water in Beaker Y.

<u>Then we get following equations:</u>

<u>First part</u>

  • x - 50 = 3/7(y + 50)
  • 7x -350 = 3y + 150
  • 7x = 3y + 500

<u>Second part</u>

  • x + 100 = 4(y - 100)
  • x + 100 = 4y - 400
  • x = 4y - 500

<u>Substitute x in first equation:</u>

  • 7(4y - 500) = 3y + 500
  • 28y - 3500 = 3y + 500
  • 28y - 3y = 500 + 3500
  • 25y = 4000
  • y = 4000/25
  • y = 160 ml

<u>Then finding x:</u>

  • x = 4*160 - 500
  • x = 640 - 500
  • x = 140 ml

Initial amount of water in Beaker X is 140 ml, in Beaker Y is 160 ml

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