Beakers X and Y contain some water. If 50 ml of water is transferred from Beaker X
1 answer:
Answer:
140 ml
Step-by-step explanation:
Let x be the amount of water in Beaker X and y be the amount of water in Beaker Y.
<u>Then we get following equations:</u>
<u>First part</u>
- x - 50 = 3/7(y + 50)
- 7x -350 = 3y + 150
- 7x = 3y + 500
<u>Second part</u>
- x + 100 = 4(y - 100)
- x + 100 = 4y - 400
- x = 4y - 500
<u>Substitute x in first equation:</u>
- 7(4y - 500) = 3y + 500
- 28y - 3500 = 3y + 500
- 28y - 3y = 500 + 3500
- 25y = 4000
- y = 4000/25
- y = 160 ml
<u>Then finding x:</u>
- x = 4*160 - 500
- x = 640 - 500
- x = 140 ml
Initial amount of water in Beaker X is 140 ml, in Beaker Y is 160 ml
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