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4 years ago

Beakers X and Y contain some water. If 50 ml of water is transferred from Beaker X

Mathematics

1 answer:

eduard4 years ago

4 0

Answer:

140 ml

Step-by-step explanation:

Let x be the amount of water in Beaker X and y be the amount of water in Beaker Y.

<u>Then we get following equations:</u>

<u>First part</u>

x - 50 = 3/7(y + 50)
7x -350 = 3y + 150
7x = 3y + 500

<u>Second part</u>

x + 100 = 4(y - 100)
x + 100 = 4y - 400
x = 4y - 500

<u>Substitute x in first equation:</u>

7(4y - 500) = 3y + 500
28y - 3500 = 3y + 500
28y - 3y = 500 + 3500
25y = 4000
y = 4000/25
y = 160 ml

<u>Then finding x:</u>

x = 4*160 - 500
x = 640 - 500
x = 140 ml

Initial amount of water in Beaker X is 140 ml, in Beaker Y is 160 ml

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