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shutvik [7]
3 years ago
9

a recipe for one batch of cookies calls 1 1/2 cups of flour how many cups of flour are needed for 3 batches

Mathematics
1 answer:
iris [78.8K]3 years ago
4 0
Since 1 batch needs 1 1/2 cups. You simply have to multiply 1 1/2 x 3.

4 1/2 cups are needed to bake 3 batches.
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Stefan sells Jin a bicycle for ​$126 and a helmet for ​$17. The total cost for Jin is 130 ​% of what Stefan spent originally to
Marina86 [1]

Answer:

Stefan originally spent $110

Stefen made $33 by selling the bicycle and helmet to jin.

Step-by-step explanation:

let ,

the original cost of bicycle and helmet for Stefan be 'x'

now,

total cost for Jin of bicycle and helmet = 126 + 17

                                                        = 143

also, total cost for Jin = 130% of original cost for Stefan

⇒ 143 = (\frac{130}{100} )x

⇒ x = 110.

hence,

profit made by Stefan = total cost for Jin - original cost for Stefan

                                     = 143 - 110

                                     = 33

5 0
4 years ago
-b-2>8 solve the inequality
vlada-n [284]

Answer:

b < 10

Step-by-step explanation:

-b - 2 > 8

Add 2 to both sides.

-b > 10

Divide both sides by -1. When dividing by a negative, flip the inequality sign.

b < 10.

7 0
3 years ago
Which steps are correct to solving this?
tankabanditka [31]

Answer:

it will mist likely be A hope this helps

5 0
3 years ago
Two buildings on opposites sides of a highway are 3x^3- x^2 + 7x +100 feet apart. One building is 2x^2 + 7x feet from the highwa
Furkat [3]

Given:

Distance between two buildings = 3x^3- x^2 + 7x +100 feet apart.

Distance between highway and one building = 2x^2 + 7x feet.

Distance between highway and second building = x^3 + 2x^2 - 18 feet.

To find:

The standard form of the polynomial representing the width of the highway between the two building.

Solution:

We know that,

Width of the highway = Distance between two buildings - Distance of both buildings from highway.

Using the above formula, we get the polynomial for width (W) of the highway.

W=3x^3- x^2 + 7x +100-(2x^2 + 7x)-(x^3 + 2x^2 - 18)

W=3x^3- x^2 + 7x +100-2x^2-7x-x^3 -2x^2+18

Combining like terms, we get

W=(3x^3-x^3)+(- x^2 -2x^2-2x^2)+ (7x -7x)+(100 +18)

W=2x^3-5x^2+0+118

W=2x^3-5x^2+118

Therefore, the width point highway is 2x^3-5x^2+118.

3 0
3 years ago
In this polygon, which angle is an interior angle?
mihalych1998 [28]

Answer:

Step-by-step explanation:

D

8 0
3 years ago
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