A) Variance = 10.24
B) Standard Deviation = 3.2
One of the measurements of dispersion is the standard deviation, which is exclusively used for quantitative data. It aids in determining if the data's mean is a suitable measurement to reflect the core value.
TIME FREQUENCY(f) MIDPOINT(x) d d² fd fd²
0 - 0.9 43 0.45 -3 9 -129 387
1.0 - 1.9 17 1.45 -2 4 -34 68
2.0 - 2.9 19 2.45 -1 1 -19 19
3.0 - 3.9 18 3.45 0 0 0 0
4.0 - 4.9 14 4.45 1 1 14 14
5.0 -5.9 16 5.45 2 4 32 64
∑f = 127
∑fd = -136
∑fd² = 552
Standard Deviation = 
√4.35 - √1.15
Standard Deviation = 3.2
(SD)² = (3.2)² = 10.24
Variance = 10.24
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The distance traveled by first car is 50t + 100.
The distance traveled by second car is 70t.
The distance between the two cars after time, t is d = 100 - 20t.
The ratio of the distance traveled by the cars is (70t) / (50t + 100).
<h3>
Distance traveled by each vehicle is calculated as follows;</h3>
The distance traveled by each vehicle at the given time is calculated as follows;
<h3>Distance traveled by first car</h3>
D₁ = speed x time
D₁ = 50(t + 2)
D₁ = 50t + 100
<h3>Distance traveled by the second car</h3>
D₂ = 70t
<h3>Distance between the two cars after time, t</h3>
d = D₁ - D₂
d = (50t + 100) - 70t
d = 100 - 20t
<h3>Ratio of the distance traveled by the cars</h3>
D₂/D₁ = (70t) / (50t + 100)
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Answer:
127 7/9
Step-by-step explanation:
144 - 2/9
144/1 - 2/9
(144×9)−(2×1)/1×9
1296-2/9
1294/9
= 143 7/9
143 7/9 - 16
= 127 7/9
Answer:
i need more context-
Step-by-step explanation:
