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3 years ago

7

PLZZZZZ HELP Two standard number cubes are thrown, one after the other. What is the probability that the first cube lands showin

g a 1 and the second cube lands showing a number that is not 1? Round the answer to the nearest thousandth.
A.
0.056
B.
0.139
C.
0.167
D.
0.278

2 answers:

Akimi4 [234]3 years ago

5 0

Answer:

Answer is b on edge202

Step-by-step explanation:

0.139

katen-ka-za [31]3 years ago

3 0

$|\Omega|=6^2=36\\ |A|=1\cdot5=5\\\\ P(A)=\dfrac{5}{36}\approx0.139$

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<u>Solution</u><u>:</u>

The rationalisation factor for $\frac{1}{ a - \sqrt{b} }$ is $a + \sqrt{b}$

So, let us apply it here.

$\frac{1}{5 - \sqrt{2} }$

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Therefore, multiplying and dividing by 5 + √2, we have

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2 years ago

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3 years ago

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Akimi4 [234]

Answer:

$t=\frac{24-25}{\frac{2.2}{\sqrt{14}}}=-1.70$

The degrees of freedom are given by:

$df=n-1=14-1=13$

The p value for this case would be given by:

$p_v =P(t_{(13)}$

Step-by-step explanation:

Information given

$\bar X=24$ represent the mean height for the sample

$s=2.2$ represent the sample standard deviation

$n=14$ sample size

$\mu_o =25$ represent the value that we want to test

t would represent the statistic

$p_v$ represent the p value for the test

Hypothesis to verify

We want to cehck if the true mean is lees than 25 mph, the system of hypothesis would be:

Null hypothesis: $\mu \geq 25$

Alternative hypothesis: $\mu < 25$

The statistic would be given by:

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Replacing the info given we got:

$t=\frac{24-25}{\frac{2.2}{\sqrt{14}}}=-1.70$

The degrees of freedom are given by:

$df=n-1=14-1=13$

The p value for this case would be given by:

$p_v =P(t_{(13)}$

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3 years ago