Answer:
3rd one and the 4th one
Step-by-step explanation:
Hopt it helps.....
Answer:
log(x^7·y^2)
Step-by-step explanation:
The applicable rules are ...
... log(a^b) = b·log(a)
... log(ab) = log(a) +log(b)
_____
The first term, 7log(x) can be rewritten as log(x^7). Note that an exponentiation operator is needed when this is written as text.
The second term 2log(y) can be rewritten as log(y^2). These two rewrites make use of the first rule above.
Now, you have the sum ...
... log(x^7) +log(y^2)
The second rule tells you this can be rewritten as ...
... log(x^7·y^2) . . . . . seems to match the intent of the 3rd selection
Answer:
A and B (2r and 7b)
Step-by-step explanation:
If she has black beans that cost $7 per pound the expression should be 7b. Hope this helps! Lmk if you have any more questions.
You have to calculate how many ways you can select six things (r)
from a set of 9 things (n). (See attached formula).
9! / 6! * (3!) =
9*8*7 * 6! / 6! * 3! =
9*8*7 / 3! =
3 * 4 * 7 = 84 lineups
Answer:
27
Step-by-step explanation:
5×6-(6/2)
=30-3
=27
