Remark
The best way to answer something like this is to actually graph both equations. I have done that for you below.
Red Line: f(x) = 1/4x - 1
Blue Line: g(x) = 1/2x - 2
Now look at the answers.
A: The first one is incorrect. You don't need the graph to tell you that. The larger the number in front of the x, the steeper the line. Put another way, the larger the slope, the steeper the line. The y intercept is lower however.
B is wrong. g(x) is steeper, but the y intercept is lower not higher than f(x) [Negatives do strange things].
C:The g(x) is steeper (we've said that a couple of times), and it has a lower y intercept.
D is correct.
E is just wrong. Both parts are incorrect.
Answer: 21.3 km
Step-by-step explanation:
Given: On each of 3 days the distance traveled by Derrick to school = 6.45 km
The distance rode by Derrick to library = 150 meters
Since, 1 m=
Thus, the distance rode by Derrick to library = 
The distance rode by Derrick to home = 500 meters.
Thus, the distance rode by Derrick to home = 
Distance he rode in each day = 
Now, Distance he rode in 3 days = 
Answer:
63
Step-by-step explanation:
7x9=63
Answer:
-5 ; 1/2
Step-by-step explanation:
<u>GIVEN :-</u>
- A quadratic polynomial f(x) = 2x² + 9x - 5
<u>TO FIND :-</u>
- Zeroes of f(x) = 2x² + 9x - 5
<u>GENERAL CONCEPTS TO BE USED IN THIS QUESTION :-</u>
Lets say there's a quadratic polynomial f(x) = ax² + bx + c , whose factors are (x - α) & (x - β). To find the values of x for which f(x) will be zero , equate the factors of f(x) with 0.
⇒ (x - α) = 0 & (x - β) = 0
⇒ x = α & x = β
Hence, it can be concluded that if (x - α) & (x - β) are factors of f(x) , then α & β are the roots of f(x).
<u>SOLUTION :-</u>
Factorise f(x) = 2x² + 9x - 5.
- Take '2x' common from first two terms & '-1' from last two terms.
- Take (x + 5) common from the whole expression.
So , the factors of f(x) are (x + 5) & (2x - 1). Now equate the factors with zero.
⇒ (x + 5) = 0 & (2x - 1) = 0
⇒ x = -5 & x = 1/2
∴ The zeroes of f(x) = 2x² + 9x - 5 are (-5) & (1/2)
<u>VERIFICATION :-</u>
1) Put x = -5 in f(x) = 2x² + 9x - 5
⇒ f(-5) = 2(-5)² + 9×(-5) - 5
= 50 - 45 - 5
= 50 - 50
= 0
2) Put x = 1/2 in f(x) = 2x² + 9x - 5
