Find 2 consecutive integers such that the sum of the first and three times the second is 11
1 answer:
Answer:
2, 3
Step-by-step explanation:
If the first integer is x, then the second is x+1. The given relation is ...
x +3(x+1) = 11
4x = 8 . . . . . . . . subtract 3
x = 2 . . . . . . . divide by 4
The integers are 2 and 3.
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<em>Check</em>
2 + 3(3) = 2+9 = 11
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First you need to multiply 11(8) = 88 then multiply 88(6) = 528 then 528/3 = 176. The answer is 176 inches
Answer:
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Step-by-step explanation:</h2><h2>|(5x-4)-3|<0.01</h2><h2>so -0.01<(5x-4-3)<0.01</h2><h2>add 7</h2><h2>7-0.01<5x<7+0.01</h2><h2>6.99<5x<7.01</h2><h2>divide by 5</h2><h2>1.398<x<1.402</h2>
Rectangle on the left = 3 × 4 = 12
Rectangle in the middle = 3 × 2 = 6
Rectangle on the right = 4 × 3 = 12
Add:
12 + 6 + 12 = 30
Answer = 30
Hope this helped☺☺
Z - 7 = 8
subtract 7 from both sides
z = 15
hope this helped!
Answer:
1 = No 2 = Yes 3 = 1.88
Step-by-step explanation: