Which of the following are solutions to the equation below? x2 + 6x + 9 =6
1 answer:
The correct answer would be 3 +/- 
In order to solve for this you must first get the equation equal to 0.
x^2 + 6x + 9 - 6 ----> simplify like terms
x^2 + 6x + 3
Now knowing this we can use the coefficients of each one in descending order of power as a, b and c.
a = 1 (because it is the coefficient to x^2)
b = 6 (because it is the coefficient to x)
c = 3 (because it is the end number)
Now we can plug these values into the quadratic equation.
3 +/-
And those would be your two answers.
In order to solve for this you must first get the equation equal to 0.
x^2 + 6x + 9 - 6 ----> simplify like terms
x^2 + 6x + 3
Now knowing this we can use the coefficients of each one in descending order of power as a, b and c.
a = 1 (because it is the coefficient to x^2)
b = 6 (because it is the coefficient to x)
c = 3 (because it is the end number)
Now we can plug these values into the quadratic equation.
3 +/-
And those would be your two answers.
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Answer:
Option a :
Step-by-step explanation:
Given :
The drama club sold 100 tickets to a show, it had $300 in profit.
The next show, it had sold a total of 200 tickets and had a total of $700 profit.
To Find : Equation models the total profit, y, based on the number of tickets sold, x
Solution :
For 100 tickets he had $300 in profit .
⇒ ()=(100,300)
For 200 tickets he had $700 in profit .
⇒ ()=(200,700)
We will use point slope form i.e.
--(A)
Now, to calculate m we will use slope formula :
Now, putting values in (A)
Thus Option a is correct i.e.
Answer:
2 hours, 150 miles
Step-by-step explanation:
The relation between time, speed, and distance can be used to solve this problem. It can work well to consider just the distance between the drivers, and the speed at which that is changing.
<h3>Separation distance</h3>Jason got a head start of 20 miles, so that is the initial separation between the two drivers.
<h3>Closure speed</h3>Jason is driving 10 mph faster than Britton, so is closing the initial separation gap at that rate.
<h3>Closure time</h3>The relevant relation is ...
time = distance/speed
Then the time it takes to reduce the separation distance to zero is ...
closure time = separation distance / closure speed = 20 mi / (10 mi/h)
closure time = 2 h
Britton will catch up to Jason after 2 hours. In that time, Britton will have driven (2 h)(75 mi/h) = 150 miles.
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<em>Additional comment</em>
The attached graph shows the distance driven as a function of time from when Britton started. The distances will be equal after 2 hours, meaning the drivers are in the same place, 150 miles from their starting spot.
