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3 years ago

Find the vertex of the equation x2-4x+5=0

Mathematics

1 answer:

amid [387]3 years ago

4 0

Answer:

(2, 1).

Step-by-step explanation:

x^2 - 4x + 5 = 0

(x - 2)^2 - 4 + 5 = 0

(x - 2)^2 + 1 = 0

The vertex is at (2, 1).

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pav-90 [236]

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3 years ago

Find the length of the curve y = 3/5x^5/3 - 3/4x^1/3 + 6 for 1 < = x < = 8. The length of the curve is . (Type an exact an

Mashutka [201]

Answer:

$\sqrt\frac{387}{20}$

Step-by-step explanation:

$Arc Length =\int\limits^a_b {\sqrt{1+(\frac{dy}{dx})^2 } } \, dx$

$y=\dfrac{3}{5}x^{\frac{5}{3}}- \dfrac{3}{4}x^{\frac{1}{3}}+6$

$\frac{dy}{dx} =x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}}$

$1+(\frac{dy}{dx})^2 }=1+(x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}})^2\\=1+(x^{\frac{4}{3}}-\dfrac{1}{2}+ \dfrac{1}{16}x^{-\frac{4}{3}})$

$=\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}}$

For the Interval $1\leq x\leq 8$

Length of the Curve $=\int\limits^8_1 {\sqrt{\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}} } } \, dx\\$

Using T1-Calculator

$=\sqrt\frac{387}{20}$

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3 years ago

How would i graph f(x)=|2x+2|−1 ?

anastassius [24]

I have attached the graph. I did this using desmos.com. Try it out sometime. I hope that helps.

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2 years ago

Point G (6,-3) is translated 5 units to the left and 6 units up to form the point g. What are the coordinates of g prime

tino4ka555 [31]

Answer:

(1,3)

Step-by-step explanation:

If a point is translated to the left it must be subtracted from the original coordinates because the left is getting closer to the negative side of the graph. If it is being translated up that number should be added, so (6-5,-3+6) which is (1,3).

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3 years ago

Find the mean of the data: 14, 9, 2, 13, 16, 3, 13, 10

svp [43]

<span>14+ 9 + 2+ 13+ 16+3+ 13+ 10 = 80
80/8 = 10

answer
mean = 10

</span>

7 0

3 years ago