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Zolol [24]
3 years ago
10

Geometry homework!!!HELP ME PLEASE!!​

Mathematics
1 answer:
Lady_Fox [76]3 years ago
5 0

f= (45*23)/35

k=(35*14)/23

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Y=-4/5x+1 is the equation for bc
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3 years ago
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What are the excluded values v^2 +1 / v^2 -v-6
valentina_108 [34]
The rational expression
\dfrac{v^{2}+1}{v^{2}-v-6}=\dfrac{v^{2}+1}{(v-3)(v+2)}
will be undefined where the denominator is zero. Values of v that make the denominator zero are v=3 and v=-2.

Excluded values of v are -2 and 3.
5 0
3 years ago
What is the measure of angle BCD?<br><br><br><br> 98<br> 110<br> 82<br> 70
Dafna11 [192]

Answer:

82

Step-by-step explanation:

opposite angles in a cyclic quadrilateral are supplimentary

4 0
2 years ago
The mean student loan debt for college graduates in Illinois is $30000 with a standard deviation of $9000. Suppose a random samp
Nataly [62]

Answer:

the probability that the mean student loan debt for these people is between $31000 and $33000 is 0.1331

Step-by-step explanation:

Given that:

Mean = 30000

Standard deviation = 9000

sample size = 100

The probability that the mean student loan debt for these people is between $31000 and $33000 can be computed as:

P(31000 < X < 33000) = P( X \leq 33000) - P (X \leq 31000)

P(31000 < X < 33000) = P( \dfrac{X - 30000}{\dfrac{\sigma}{\sqrt{n}}} \leq \dfrac{33000 - 30000}{\dfrac{9000}{\sqrt{100}}}    )- P( \dfrac{X - 30000}{\dfrac{\sigma}{\sqrt{n}}} \leq \dfrac{31000 - 30000}{\dfrac{9000}{\sqrt{100}}}    )

P(31000 < X < 33000) = P( Z \leq \dfrac{33000 - 30000}{\dfrac{9000}{\sqrt{100}}}    )- P(Z \leq \dfrac{31000 - 30000}{\dfrac{9000}{\sqrt{100}}}    )

P(31000 < X < 33000) = P( Z \leq \dfrac{3000}{\dfrac{9000}{10}}}) -P(Z \leq \dfrac{1000}{\dfrac{9000}{10}}})

P(31000 < X < 33000) = P( Z \leq 3.33)-P(Z \leq 1.11})

From Z tables:

P(31000 < X

P(31000 < X

Therefore; the probability that the mean student loan debt for these people is between $31000 and $33000 is 0.1331

8 0
3 years ago
What is the following quotient? 5/√11-√3
kati45 [8]

ANSWER

\frac{5( \sqrt{11}  +  \sqrt{3} )} {8}

EXPLANATION

The given rational function is

\frac{5}{ \sqrt{11} -  \sqrt{3}}

We need to rationalize the denominator by multiplying both the numerator and the denominator by the conjugate of

\sqrt{11}  -  \sqrt{3}

which is

\sqrt{11}   +  \sqrt{3}

When we rationalize we obtain:

\frac{5( \sqrt{11}  +  \sqrt{3} )}{(\sqrt{11}  - \sqrt{3} )( \sqrt{11}  +  \sqrt{3} )}

The denominator is now a difference of two squares:

(a - b)(a + b) =  {a}^{2}  -  {b}^{2}

We apply this property to get

\frac{5( \sqrt{11}  +  \sqrt{3} )}{( \sqrt{11}) ^{2}    -  ( \sqrt{3}) ^{2}  )}

\frac{5( \sqrt{11}  +  \sqrt{3} )}{11   -  3}

This simplifies to

\frac{5( \sqrt{11}  +  \sqrt{3} )} {8}

Or

\frac{5 }  {8}\sqrt{11}  + \frac{5 }  {8}\sqrt{3}

8 0
3 years ago
Read 2 more answers
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