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Blizzard [7]
4 years ago
13

What is [5 (2+1)] to the Second power + 10

Mathematics
1 answer:
erastova [34]4 years ago
5 0

Answer:

235

Step-by-step explanation:

[5 (2+1)]^2 + 10

[5*3]^2 + 10

15^2 + 10

225 + 10

235

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anne buys onions and tomatoes. onions cost $1.09 per pound and tomatoes cost $1.29 per pound. the cost of anne's produce is repr
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X is the amount of pounds. 
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3 years ago
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(a) Consider a class with 30 students. Compute the probability that at least two of them have their birthdays on the same day. (
Galina-37 [17]

Answer:

a.) 0.7063

b.) 23

Step-by-step explanation:

a.)

Let X be an event in which at least 2 students have same birthday

     Y be an event in which no student have same birthday.

Now,

P(X) + P(Y) = 1

⇒P(X) = 1 - P(Y)

as we know that,

Probability of no one has birthday on same day = P(Y)

⇒P(Y) = \frac{365!}{(365)^{n} (365-n)! }      where there are n people in a group

As given,

n = 30

⇒P(Y) = \frac{365!}{(365)^{30} (365-30)! } = \frac{365!}{(365)^{30} (335)! } = 0.2937

∴ we get

P(X) = 1 - 0.2937 = 0.7063

So,

The probability that at least two of them have their birthdays on the same day  =  0.7063

b.)

Given, P(X) > 0.5

As

P(X) + P(Y) = 1

⇒P(Y) ≤ 0.5

As

P(Y) = \frac{365!}{(365)^{n} (365-n)! }

We use hit and trial method

If n = 1 , then

P(Y) = \frac{365!}{(365)^{1} (365-1)! } = \frac{365!}{(365)^{1} (364)! }  = 1 \nleq 0.5

If n = 5 , then

P(Y) = \frac{365!}{(365)^{5} (365-5)! } = \frac{365!}{(365)^{5} (360)! }  = 0.97 \nleq 0.5

If n = 10 , then

P(Y) = \frac{365!}{(365)^{10} (365-10)! } = \frac{365!}{(365)^{10} (354)! }  = 0.88 \nleq 0.5

If n = 15 , then

P(Y) = \frac{365!}{(365)^{15} (365-15)! } = \frac{365!}{(365)^{15} (350)! }  = 0.75 \nleq 0.5

If n = 20 , then

P(Y) = \frac{365!}{(365)^{20} (365-20)! } = \frac{365!}{(365)^{20} (345)! }  = 0.588 \nleq 0.5

If n = 22 , then

P(Y) = \frac{365!}{(365)^{22} (365-22)! } = \frac{365!}{(365)^{22} (343)! }  = 0.52 \nleq 0.5

If n = 23 , then

P(Y) = \frac{365!}{(365)^{23} (365-23)! } = \frac{365!}{(365)^{23} (342)! }  = 0.49 \nleq 0.5

∴ we get

Number of students should be in class in order to have this probability above 0.5 = 23

5 0
3 years ago
The figure is made up of a cone and hemisphere. To the nearest whole number, what is the volume of this figure? Use 3.14 to appr
Finger [1]

Answer:

Volume=469cm³

Step-by-step explanation:

[tex]

Volume,V=Volume Cone + Volume\ of Hemisphere\\\\

Volume Cone,V1=\pi*r^2*\frac{h}{3}=\pi*4^2*\frac{12}{3}\\    \\

                     =201.06cm^3\\

Volume of Hemisphere,V2=2*\pi*\frac{r^3}{3}\\

                                            =2*\pi*\frac{4^3}{3}=268.083cm^3\\

Volume=V1+V2=201.06+268.08\\

            =469cm^3

[\tex]

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Vail Ski Shop received a $1,201 invoice dated July 8 with 2/10, 1/15, n/60 terms. On July 22, Vail sent a $485 partial payment.
suter [353]
A)
100%-1%=99%=0.99
485/0.99=489.9
489.9 is the amount of payment to be credited

B)
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Answer:

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