Answer:
a.) 0.7063
b.) 23
Step-by-step explanation:
a.)
Let X be an event in which at least 2 students have same birthday
Y be an event in which no student have same birthday.
Now,
P(X) + P(Y) = 1
⇒P(X) = 1 - P(Y)
as we know that,
Probability of no one has birthday on same day = P(Y)
⇒P(Y) =
where there are n people in a group
As given,
n = 30
⇒P(Y) =
= 0.2937
∴ we get
P(X) = 1 - 0.2937 = 0.7063
So,
The probability that at least two of them have their birthdays on the same day = 0.7063
b.)
Given, P(X) > 0.5
As
P(X) + P(Y) = 1
⇒P(Y) ≤ 0.5
As
P(Y) =
We use hit and trial method
If n = 1 , then
P(Y) =
= 1
0.5
If n = 5 , then
P(Y) =
= 0.97
0.5
If n = 10 , then
P(Y) =
= 0.88
0.5
If n = 15 , then
P(Y) =
= 0.75
0.5
If n = 20 , then
P(Y) =
= 0.588
0.5
If n = 22 , then
P(Y) =
= 0.52
0.5
If n = 23 , then
P(Y) =
= 0.49
0.5
∴ we get
Number of students should be in class in order to have this probability above 0.5 = 23
Answer:
Volume=469cm³
Step-by-step explanation:
[tex]
Volume,V=Volume Cone + Volume\ of Hemisphere\\\\
Volume Cone,V1=\pi*r^2*\frac{h}{3}=\pi*4^2*\frac{12}{3}\\ \\
=201.06cm^3\\
Volume of Hemisphere,V2=2*\pi*\frac{r^3}{3}\\
=2*\pi*\frac{4^3}{3}=268.083cm^3\\
Volume=V1+V2=201.06+268.08\\
=469cm^3
[\tex]
A)
100%-1%=99%=0.99
485/0.99=489.9
489.9 is the amount of payment to be credited
B)
1,201−489.9=711.1 is the balance outstanding
Answer:
2k+7
Step-by-step explanation:
4k - 1 ( 2k - 7 )
4k-2k +7