11 school days are left.
In the attached picture of a calendar, I marked the days the person has left. There are 11.
The answer to your question would be 6!
Answer:
5) x = 1, y = -3
6) x = -20, y = 2
7) infinite solutions
8) no solutions
Step-by-step explanation:
5)
y = 5x - 8
y = -6x + 3
5x - 8 = -6x + 3
11x = 11
x = 1
y = 5 - 8
y = -3
6)
2x + 10y = -20
-x + 4y = 28
2x = -20 - 10y
x = - 10 - 5y
-x = 28 - 4y
x = -28 + 4y
-10 - 5y = -28 + 4y
-10 + 28 = 4y + 5y
18 = 9y
2 = y
2x + 20 = -20
2x = -40
x = -20
7)
this has infinite solutions because one equation is a simplified version of the other
8)
this has no solutions because 5 does not equal -5
9)
I can't graph on brainly, hope this helped though
Answer:
d. 690.1 units²
Step-by-step explanation:
1. You can use the Heron's formula to calculate the area of the triangle, which is:
![K=\sqrt{s(s-a)(s-b)(s-c)}](https://tex.z-dn.net/?f=K%3D%5Csqrt%7Bs%28s-a%29%28s-b%29%28s-c%29%7D)
Where:
![s=\frac{a+b+c}{2}](https://tex.z-dn.net/?f=s%3D%5Cfrac%7Ba%2Bb%2Bc%7D%7B2%7D)
2. Calculate
:
![s=\frac{33+51+42}{2}\\s=63](https://tex.z-dn.net/?f=s%3D%5Cfrac%7B33%2B51%2B42%7D%7B2%7D%5C%5Cs%3D63)
3. Substitute values into the formula shown above and calculate the area, as following:
![K=\sqrt{63(63-33)(63-51)(63-42)}\\K=690.1units^{2}](https://tex.z-dn.net/?f=K%3D%5Csqrt%7B63%2863-33%29%2863-51%29%2863-42%29%7D%5C%5CK%3D690.1units%5E%7B2%7D)
4. Therefore, the area is 690.1 units².