The quotient of 6x^3+2x^2−x and x is 6x^3+2x^2−x divided by x
The value of the quotient 6x^3+2x^2−x by x is 6x^2 + 2x - 1
<h3>How to determine the quotient</h3>
The quotient expression is given as:
6x^3+2x^2−x divide by x
The above means that,
We divide 6x^2 by x, we divide 2x^2 by x and we divide -x by x.
So, we have:
6x^3+2x^2−x divide by x = 6x^2 + 2x - 1
Hence, the value of the quotient 6x^3+2x^2−x is 6x^2 + 2x - 1
Read more about quotient at:
brainly.com/question/7068223
Answer:here is the answer on yt
Step-by-step explanation:
https://youtu.be/dQw4w9WgXcQ
Answer:
Step-by-step explanation:
so, by the Pythagorean theorem
If it is a right triangle:
a^2 + b^2 = c^2
so,
6^2 = 36
8^2 = 64
10^2 = 100
okay, now we plug these into the equation
36 + 64 = 100
so yes, it is a right triangle.
Hope this helped!
Answer:
<em>y </em>= 8<em>x</em>
Step-by-step explanation:
The slope is 8, the y-intercept is 0. The slope-intercept form is written:
<em>y</em> = <em>mx</em> +<em> b</em>
So this situation would be written <em>y = </em>8<em>x </em>+ 0 or just <em>y</em> = 8<em>x.</em>
Hope it helps!
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