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3 years ago

A trapezoid has an area of 50 square inches. The bases are 3 inches and 7 inches. What is the height of the trapezoid

Mathematics

1 answer:

Nostrana [21]3 years ago

5 0

Answer:

H = 10 inches

Step-by-step explanation:

The fomula for area of a trapezoid is

A = (1/2)(B1 + B2)H

where B1 is a base, B2 is the other base, and H is the height

It reads as "Area is one half the product of the sum of the bases and the height"

Plug in what you are given and solve for H. We are given A, B1, and B2

50 = (1/2)(3 + 7)H

50 = (1/2)(10)H (simplify the parenthesis first)

50 = 5H (simplify the right side)

10 = H (divide by 5 on both sides to isolate H)

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2 – $20.00 bills, 1 – $10.00 bill, 1 – $5.00 bill, 2 – $1.00 bills, 3 – quarters, 1 – dime, 1 – nickel, and 4 pennies

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3 years ago

Between 2000 and 2015 , the number of twin births in a certain country increased by 11%, to approximately128,760 . About how m

Lana71 [14]

Answer:

116000

Step-by-step explanation:

The number of twins in 2000 is x

the number increases by 11% to year 2015

x(1+11/100 )=128760

x+0.11x=128760

1.11x=128760

x=128760/1.11

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8 0

3 years ago

What is the antiderivative of e^x^2?

ddd [48]

Answer: The antiderivative of $e^{x^{2}}$ is $\sqrt{\pi} \sqrt{e^{x^2}-1} +C$ .

Explanation:

$I=\int{e^{x^2}dx}\\I^2=\int{e^{x^2}dx}\int{e^{x^2}dx}$

Using dawson integral.

$I^2=\int{e^{x^2}dx}\int{e^{y^2}dy}$

$I^2=\int{\int{e^{x^2+y^2}dxdy}}$

Put $x^2+y^2=r^2$

$I^2=\int{\int{e^{r^2}rdrd\theta}}$

$\int_{0}^{2\pi}{d\theta}\int_{0}^{x}{re^{r^2}dr}$

Use substitution method and sunbstitute $r^2=t$ .

$\int_{0}^{2\pi}{d\theta}\int_{0}^{x^2}{\frac{1}{2}e^tdt}$

$I^2=\frac{1}{2}|\theta|_{0}^{2\pi}|e^t|_{0}^{x^2}\\I^2=\frac{1}{2}(2\pi)(e^{x^2}-1)\\I=\sqrt{\pi}\sqrt{e^{x^2}-1}$ .

Therefore, the antiderivative of $e^{x^{2}}$ is $\sqrt{\pi} \sqrt{e^{x^2}-1} +C$ .

4 0

4 years ago

P(x)equals=R(x)minus−C(x). Given R(x)equals=59 x minus 0.3 x squared59x−0.3x2 and Upper C left parenthesis x right parenthesi

Deffense [45]

Answer:

$P(x)=-0.3x^2+56x-14$

Step-by-step explanation:

The given functions are

$R(x)=59x-0.3x^2$

$C(x)=3x+14$

It is given that

$P(x)=R(x)-C(x)$

Substitute the values of given functions in the above equation.

$P(x)=59x-0.3x^2-(3x+14)$

$P(x)=59x-0.3x^2-3x-14$

Combine like terms.

$P(x)=-0.3x^2+(59x-3x)-14$

$P(x)=-0.3x^2+56x-14$

Therefore, the required function is $P(x)=-0.3x^2+56x-14$ .

4 0

4 years ago

Adding mixed numbers. Can someone help me correct my answer?

Olin [163]

Answer:

27 13/60

Step-by-step explanation:

What you have tried to do is not an impossible way to do it. What you could do is set your fractions and whole numbers like this.

( 7 + 1/10) * (3 + 5/6) I don't know if you know what FOIL is, but that is the way to proceed.

First: (meaning the first in each factor ). 3 * 7 = 21
Outside: (meaning the two terms near outside the brackets) 7 * 5/6 = 5 5/6
Inside: The two terms closest to the * sign 1 / 10 *3 = 3/10
Last: The two end terms (1/10 * 5/6 = 5/60 5/60

Now you can add. 21 + 5 is the whole number amount = 26

Add the fractions

5/6 + 3/10 + 5/60 The lowest common multiple is 60
50/60 + 18/60 +5/60 = 73 / 60 = 1 and 13/60

Add that to 26 and you get 27 13/60

3 0

3 years ago