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3 years ago

Adding mixed numbers. Can someone help me correct my answer?

Mathematics

1 answer:

Olin [163]3 years ago

3 0

Answer:

27 13/60

Step-by-step explanation:

What you have tried to do is not an impossible way to do it. What you could do is set your fractions and whole numbers like this.

( 7 + 1/10) * (3 + 5/6) I don't know if you know what FOIL is, but that is the way to proceed.

First: (meaning the first in each factor ). 3 * 7 = 21
Outside: (meaning the two terms near outside the brackets) 7 * 5/6 = 5 5/6
Inside: The two terms closest to the * sign 1 / 10 *3 = 3/10
Last: The two end terms (1/10 * 5/6 = 5/60 5/60

Now you can add. 21 + 5 is the whole number amount = 26

Add the fractions

5/6 + 3/10 + 5/60 The lowest common multiple is 60
50/60 + 18/60 +5/60 = 73 / 60 = 1 and 13/60

Add that to 26 and you get 27 13/60

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A baby who was 18 inches at birth is now 24 inches by what percentage did the babys height increase

Kazeer [188]

Answer:

≈33.3%

Step-by-step explanation:

First we find the difference of the heights to see what the growth was

24-18 = 6

Then we find what percent 6 is of 18 to see what percentage growth occured

6/18 ≈33.3%

8 0

2 years ago

A sample of 15 commuters in Chicago showed the average of the commuting times was 33.2 minutes. If s = 8.3 minutes, find the 95%

OleMash [197]

Answer:

The 95% confidence interval of the true mean.

(29.4261 ,36.9739)

Step-by-step explanation:

Step :- (i)

Given sample size 'n' =15

sample of the mean x⁻ = 33.2

The standard deviation of the sample 'S' = 8.3

95% of confidence intervals

$(x^{-} - t_{\alpha } \frac{S}{\sqrt{n} } ,x^{-} + t_{\alpha }\frac{S}{\sqrt{n} } )$

Step:-(ii)

The degrees of freedom γ=n-1 = 15-1=14

The tabulated value t = 1.761 at 0.05 level of significance.

now substitute all possible values, we get

$(33.2 - 1.761\frac{8.3}{\sqrt{15} } ,33.2+ 1.761\frac{8}{\sqrt{15} } )$

After calculation , we get

(33.2-3.7739 , 33.2+3.7739

(29.4261 ,36.9739)

Conclusion:-

the 95% confidence interval of the true mean.

(29.4261 ,36.9739)

8 0

3 years ago

CALCULUS: For the function whose values are given in the table below, the integral from 0 to 6 of f(x)dx is approximated by a Re

ladessa [460]

The table gives values of f(x) at various x in the interval [0, 6], and you have to use them to approximate the definite integral,

∫₀⁶ f(x) dx

with a left-endpoint sum using 3 intervals of width 2. This means you have to

• split up [0, 6] into 3 subintervals of equal length, namely [0, 2], [2, 4], and [4, 6]

• take the left endpoints of these intervals and the values of f(x) these endpoints, so x ∈ {0, 2, 4} and f(x) ∈ {0, 0.48, 0.84}

• approximate the area under f(x) on [0, 6] with the sum of the areas of rectangles with dimensions 2 × f(x) (that is, width = 2 and height = f(x) for each rectangle)

So the Riemann sum is

∫₀⁶ f(x) dx ≈ 2 ∑ f(x)

for x ∈ {0, 2, 4}, which is about

∫₀⁶ f(x) dx ≈ 2 (0 + 0.48 + 0.84) = 2.64

making the answer A.

7 0

2 years ago

Express f(x) = |x-2| +|x+2| in the non-modulus form. Hence, sketch the graph of f.

alexgriva [62]

Recall that

$|x|=\begin{cases}x&\text{if }x\ge0\\-x&\text{if }x$

There are three cases to consider:

(1) When $x+2$ , we have $|x+2|=-(x+2)$ and $|x-2|=-(x-2)$ , so

$|x-2|+|x+2|=-(x-2)-(x+2)=-2x-4$

(2) When $x+2\ge0$ and $x-2$ , we get $|x+2|=x+2$ and $|x-2|=-(x-2)$ , so

$|x-2|+|x+2|=-(x-2)+(x+2)=4$

(3) When $x-2\ge0$ , we have $|x+2|=x+2$ and $|x-2|=x-2$ , so

$|x-2|+|x+2|=(x-2)+(x+2)=2x$

So

$|x-2|+|x+2|=\begin{cases}-2x-4&\text{if }x$

4 0

2 years ago

Given the piecewise function shown below, select all the statements that are true.

Lena [83]

C
because it is the only logical answer

4 0

3 years ago