Please help me answer these 2 questions

1 answer:

4 0

The first one is not a question. Rather it is the parameters in which the second question exists.

2.

49.85%

This is because the likelihood of a point being within 2 SDs of the mean is 99.7%. This leaves .15 above and .15 below that curve. Given that we are looking from the mean (50%) and the upper limit with the exception of that .15, we would get the answer above.

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A line is perpendicular to y = -1/5x+1

natta225 [31]

Answer:

$y = 5\, x + 26$ .

Step-by-step explanation:

Start by finding the slope of the line perpendicular to $y = (-1/5)\, x + 1$ .

The slope of $y = (-1/5)\, x + 1$ is $(-1/5)$ .

In a plane, if two lines are perpendicular to one another, the product of their slopes would be $(-1)$ .

Let $m$ denote the slope of the line perpendicular to $y = (-1/5)\, x + 1$ . The expression $(-1/5)\, m$ would denote the product of the slopes of these two lines.

Since these two lines are perpendicular to one another, $(-1/5)\, m = -1$ . Solve for $m$ : $m = 5$ .

The $(-5,\, 1)$ is a point on the requested line. (That is, $x_{1} = -5$ and $y_{1} = 1$ .) The slope of that line is found to be $m = 5$ . The equation of that line in the point-slope form would be: