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worty [1.4K]
3 years ago
8

Please help me answer these 2 questions

Mathematics
1 answer:
Fittoniya [83]3 years ago
4 0
The first one is not a question. Rather it is the parameters in which the second question exists.

2. 

49.85%

This is because the likelihood of a point being within 2 SDs of the mean is 99.7%. This leaves .15 above and .15 below that curve. Given that we are looking from the mean (50%) and the upper limit with the exception of that .15, we would get the answer above. 
You might be interested in
The points (3, 24) and (7, 56) represent points of a function where y, the number of photographs, varies directly with x, the nu
tester [92]
(3,24)(7,56)
slope = (56 - 24) / (7 - 3) = 32/4 = 8

y = mx + b
slope(m) = 8
(3,24)...x = 3 and y = 24
now we sub
24 = 8(3) + b
24 = 24 + b
24 - 24 = b
0 = b

so ur equation is : y = 8x + 0...or just y = 8x

to find ur answer, take ur answer choices and sub them into y = 8x and whichever one is true is ur answer.
6 0
4 years ago
Read 2 more answers
I need to know the answer to this lol
asambeis [7]
Length of GH is also 11 meters
5 0
4 years ago
Read 2 more answers
A rhombus with right angles
Ghella [55]

Answer:

A rhombus is quadrilateral with all side of equal length. Thus a quadrilateral with all sides of equal length and all angles right angles is still a rhombus but it is also a square. It is also a quadrilateral, a rectangle and a parallelogram.

Step-by-step explanation:

I hope this helped! have a great day! :)

7 0
3 years ago
Don't get this
kap26 [50]
I'll talk you through it so you can see why it's true, and then
you can set up the 2-column proof on your own:

Look at the two pointy triangles, hanging down like moth-wings
on each side of 'OC'.

-- Their long sides are equal,  OA = OB, because both of those lines
are radii of the big circle.

-- Their short sides are equal, OC = OC, because they're both the same line.

-- The angle between their long side and short side ... the two angles up at 'O',
are equal, because OC is the bisector of the whole angle there.

-- So now you have what I think you call 'SAS' ... two sides and the included angle of one triangle equal to two sides and the included angle of another triangle.
(When I was in high school geometry, this was not called 'SAS' ... the alphabet
did not extend as far as 'S' yet, and we had to call this congruence theorem
"broken arrow".)

These triangles are not congruent the way they are now, because one is
the mirror image of the other one.  But if you folded the paper along 'OC',
or if you cut one triangle out and turn it over, it would exactly lie on top of
the other one, and they would be congruent.

So their angles at 'A' and at 'B' are also equal ... those are the angles that
you need to prove equal.
5 0
4 years ago
What is the length of chord An in Oo below?
Anika [276]

Answer:

12 units

Step-by-step explanation:

In\: \odot O,

  • chords \overline{ML} and \overline{AN} are equidistant (7.2 units) from the center of the circle O.
  • Measures of the chords equidistant from the center of the circle are equal.
  • \therefore m(chord\:\overline{AN}) =m(chord\:\overline{ML})
  • \because m(chord\:\overline{ML}) = 12\: units
  • \therefore m(chord\:\overline{AN}) = 12\: units
4 0
3 years ago
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