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ehidna [41]
4 years ago
14

Please help me!..........

Mathematics
1 answer:
Anastaziya [24]4 years ago
4 0

Answer:

<h2>$39,000</h2>

Step-by-step explanation:

Look at the picture.

To find the Median, place the numbers in value order and find the middle number (right picture).

Median = $39,000

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6 0
3 years ago
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If p-1 is a factor of p^4+p^2+p-k the value of k is
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7 0
4 years ago
(a+b+c)(d+e+f)(a+b+c)(d+e+f)(a+ b+ c) <br> ( d+e+ f)
8090 [49]

Hi the expanded form is

d^3 a^3 + e^3 a^3 + f^3 a^3 + 3 d e^2 a^3 + 3 d f^2 a^3 + 3 e f^2 a^3 + 3 d^2 e a^3 + 3 d^2 f a^3 + 3 e^2 f a^3 + 6 d e f a^3 \\+ 3 b d^3 a^2 + 3 c d^3 a^2 \\+ 3 b e^3 a^2 + 3 c e^3 a^2 + 3 b f^3 a^2 \\+ 3 c f^3 a^2 + 9 b d e^2 a^2 + 9 c d e^2 a^2 + 9 b d f^2 a^2 + 9 c d f^2 a^2\\ + 9 b e f^2 a^2 + 9 c e f^2 a^2 + 9 b d^2 e a^2 + 9 c d^2 e a^2 + 9 b d^2 f a^2 + 9 c d^2 f a^2 \\+ 9 b e^2 f a^2 + 9 c e^2 f a^2 + 18 b d e f a^2

+ 18 c d e f a^2 + 3 b^2 d^3 a + 3 c^2 d^3 a \\+ 6 b c d^3 a + 3 b^2 e^3 a + 3 c^2 e^3 a + 6 b c e^3 a + 3 b^2 f^3 a \\+ 3 c^2 f^3 a + 6 b c f^3 a + 9 b^2 d e^2 a \\+ 9 c^2 d e^2 a + 18 b c d e^2 a + 9 b^2 d f^2 a\\ + 9 c^2 d f^2 a + 18 b c d f^2 a + 9 b^2 e f^2 a + 9 c^2 e f^2 a + 18 b c e f^2 a + 9 b^2 d^2 e a \\+ 9 c^2 d^2 e a + 18 b c d^2 e a + 9 b^2 d^2 f a + 9 c^2 d^2 f a + 18 b c d^2 f a \\+ 9 b^2 e^2 f a + 9 c^2 e^2 f a + 18 b c e^2 f a

+ 18 b^2 d e f a + 18 c^2 d e f a + 36 b c d e f a \\+ b^3 d^3 + c^3 d^3 + 3 b c^2 d^3 + 3 b^2 c d^3 + b^3 e^3 + c^3 e^3 \\+ 3 b c^2 e^3 + 3 b^2 c e^3 + b^3 f^3 + c^3 f^3 + 3 b c^2 f^3 + 3 b^2 c f^3 + 3 b^3 d e^2 \\+ 3 c^3 d e^2 + 9 b c^2 d e^2 + 9 b^2 c d e^2 + 3 b^3 d f^2 + 3 c^3 d f^2 + 9 b c^2 d f^2 \\+ 9 b^2 c d f^2 + 3 b^3 e f^2 + 3 c^3 e f^2

+ 9 b c^2 e f^2 + 9 b^2 c e f^2 + 3 b^3 d^2 e \\+ 3 c^3 d^2 e + 9 b c^2 d^2 e + 9 b^2 c d^2 e + 3 b^3 d^2 f + 3 c^3 d^2 f \\+ 9 b c^2 d^2 f + 9 b^2 c d^2 f + 3 b^3 e^2 f + 3 c^3 e^2 f + 9 b c^2 e^2 f \\+ 9 b^2 c e^2 f + 6 b^3 d e f + 6 c^3 d e f + 18 b c^2 d e f + 18 b^2 c d e f

8 0
3 years ago
Help asap i think im doing it wrong
Misha Larkins [42]
Part 1.
A. x=0 can be used for function that have x≤1, so f(x) =x²
B.You need substitute x by 0. x=0,
then

f(0) = 1) x² =0² =0      x≤1 
         
Part 2.
A. f(x) =x², Graph is attached. 
B. f(x) =2x+1, Graph is attached.
C. The functions will change in the point x=1
For f(x) =x² , x ≤1 ; f(1) = 1. The point (1,1) is included, the dot should be filled (closed).
For the function f(x)=2x+1, x>1. The point  f(1)=3 is not included, the dot should be empty(open).
D. Point(1,1) is closed(filled circle), point (1,3) is open(empty circle).

4 0
4 years ago
Manuel made 5 identical necklaces, each having beads and a pendant. The total cost of the beads and pendants for all 5 necklaces
valentinak56 [21]

Answer:

2.3

Step-by-step explanation:

Step 1: Divide 30.50 by 5 to get that each necklaces costs 6.1.

Step 2: Subtract 6.1 (cost for 1 necklace) and 3.80 (price of beads)

Your answer is 2.3! Please mark this as brainliest

4 0
4 years ago
Read 2 more answers
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