<span>(1 + 1) ÷ 2 + 1 <span>answer is 2.
Here are the steps.
1. Reduce 1 + 1 to 2 ( 2 </span>÷ 2 + 1).
2. Reduce 2 ÷ 2 to 1 ( 1 + 1).
3. So finally the answer is 2.</span>
Answer:
The probability of 1 or less children from that group to learn how to swim before 6 years of age is 0.072
Step-by-step explanation:
In this case we need to compute the probability of none of these 12 children learns to swim before 6 years of age. This is given by:
p(0) = (1 - 0.312)^(12) = 0.688^(12) = 0.01124
We now need to calculate the probability that one child learns to swim before 6 years of age.
p(1) = 12*0.312*(1 - 0.312)^(11) = 3.744*(0.688)^(11)
p(1) = 3.744*0.01634
p(1) = 0.0612
The probability of 1 or less children from that group to learn how to swim before 6 years of age is:
p = p(0) + p(1) = 0.01124 + 0.0612 = 0.07244
Hello!
Let's write this as an equation.
74x=66
Now let's solve by dividing both sides by 74.
x≈0.89
Now we multiply by 100 to make it a percent.
0.89(100)= 89
Therefore, our answer is 89%
I hope this helps!
Use the formula
y+2=-5/7(x+1)
solve and you will get the equation which is
f(x)=-5/7(x)-19/7
