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Gre4nikov [31]
3 years ago
11

Between which two consecutive whole numbers is

le=" \sqrt{46} " alt=" \sqrt{46} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
tia_tia [17]3 years ago
3 0
You have to find which perfect square numbers are closest to 46. The list is 1, 4, 9, 16, 25, 36, 49, 64... we can stop there. 

46 falls between 36 and 49, which is 6 and 7 squared. So the answer is 6 and 7.
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Answer:you need common denominatord 4*2=8 3*2=6 6/8+1/8=7/8 of sugar

Step-by-step explanation:

3 0
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Can you help me factor 24p + 64
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5 0
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Suppose $886.20 is listed for $5 less. A third catalog has $886.20 marked down 20% ,which is the better deal?
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4 0
3 years ago
In a large population, 60% of the people have been vaccinated. If 4 people are randomly selected, what is the probability that A
gulaghasi [49]

Answer:

0.9744 probability that AT LEAST ONE of them has been vaccinated

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they have been vaccinated, or they have not. The probability of a person having been vaccinated is independent of any other person. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

60% of the people have been vaccinated.

This means that p = 0.6

If 4 people are randomly selected, what is the probability that AT LEAST ONE of them has been vaccinated?

This is

P(X \geq 1) when n = 4.

We have that

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{4,0}.(0.6)^{0}.(0.4)^{4} = 0.0256

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0256 = 0.9744

0.9744 probability that AT LEAST ONE of them has been vaccinated

5 0
3 years ago
What is a third in 420
kolezko [41]
420/3 = 140 rubies
Since they use 20 rubies you would do the total amount of rubies by 20.
140/20 = 7
7 0
3 years ago
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