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3 years ago

How do i go about solving the following system of equations by elimination?

1 answer:

8 0

Divide the second equation by 2
4m-3n=18
multiply by -1
-4m+3n=-18
add to first equation
4m-4m+3n-3n=27-18
0=9
false
there is no solution

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From a point P outside line segment AB =6cm, construct a line PQ parallel to line segment AB.

goldfiish [28.3K]

Answer:

We drawn the graph.

Step-by-step explanation:

We have a line segment AB = 6cm and a point P outside that a line segment.

We want to construct a line PQ that is parallel to line segment AB.

If PQ is parallel to longer AB, this means that a line PQ is equidistant from line segment AB everywhere.

We use the geogebra.org site to draw it.

We drawn the graph.

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4 years ago

How to find 8x4 by using Distributive property

joja [24]

4(2x1) ahdnwixkeobej <—- ignore that I just needed to type 20 characters

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It cost a general mission fee of $6 to get into the fair and then $1 what you tried. Which of the following equations would repr

jonny [76]

F(x) = 6 + x
6 is a one time admission fee. Each ride would cost $1, so you would just add 1 into the admission fee to see what you paid total.

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4 years ago

I need help on this question I’m confused I think a &b are the same and c &d are different but I’m not to sure !

Nina [5.8K]

<h3>Answer: They're all the same</h3>

====================================================

Reason:

$2^6$ means we have 6 copies of "2" multiplied out as shown in choice B. That explains how A and B are the same, and we can say

$2^6 = (2*2*2)*(2*2*2)$

The parenthesis are optional, but I find they're handy to count the '2's easier.

----------------

Now notice that

$2^3 = 2*2*2$

So,

$2^6 = (2*2*2)*(2*2*2)\\\\2^6 = (2^3)*(2^3)\\\\2^6 = (2^3)^2\\\\$

The last step is possible because we have two copies of $2^3$ multiplied together.

This shows that choice C is equivalent to A and B.

-------------------

Lastly,

$2^6 = (2*2*2)*(2*2*2)\\\\2^6 = (2*2)*(2*2)*(2*2)\\\\2^6 = (2^2)*(2^2)*(2^2)\\\\2^6 = (2^2)^3\\\\$

The jump to the last step is possible because we have three copies of $2^2$ multiplied together.

This shows choice D is equivalent to the others.

All four expressions are the same.

They represent different ways to say the same number. That number being 64.

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2 years ago

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VashaNatasha [74]

The first five multiples of 9 are
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3 years ago

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