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3 years ago

Which of the following is a pair of vertical angles ?

Mathematics

2 answers:

beks73 [17]3 years ago

6 0

Answer

∠AOB and ∠DOC are a pair of vertical angle

Step-by-step explanation

Given in the figure we have to choose the angle which are vertically opposite to each other.

The vertically opposite angles are the angles vertically opposite when two line cross each other.

Option A

∠AOB and∠DOC are vertically opposites to each other so they are a pair of vertical angle

Option B

∠AOB and∠EOA are not vertically opposite to each other so they are not a pair of vertical angle.

Option C

∠DOC and ∠EOB are not vertically opposite to each other so they are also not a pair of vertical angles .

Option D

∠EOB and∠EOA are also not vertically opposite to each other so they are also not a pair of vertical angle

Therefore, ∠AOB and ∠DOC are a pair of vertical angles

nikklg [1K]3 years ago

5 0

Vertical angles are the angles opposite each other when two lines cross, so
∠AOB and ∠DOC are vertical.

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Nathan went shopping for a new camera because of a sale. The store was offering a 40% discount. If the price on the tag was $35,

tia_tia [17]

Answer:

The price after the discount but before the tax is $21

Step-by-step explanation:

Here, we are told there is a price off of 40% on an item that costs $35.

What we want to calculate is the value of what the price would be before the tax

We proceed by finding 40% of $35

Mathematically, that would be;

40/100 * 35 = $14

The price of the item before the tax is thus;

35-14 = $21

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2 years ago

The Precision Scientific Instrument Company manufactures thermometers that are supposed to give readings of 0degrees°C at the fr

Sergio039 [100]

Answer:

Step-by-step explanation:

Hello!

The variable of study is X: Temperature measured by a thermometer (ºC)

This variable has a distribution approximately normal with mean μ= 0ºC and standard deviation σ= 1.00ºC

To determine the value of X that separates the bottom 4% of the distribution from the top 96% you have to work using the standard normal distribution:

P(X≤x)= 0.04 ⇒ P(Z≤z)=0.04

First you have to use the Z tables to determine the value of Z that accumulates 0.04 of probability. It is the "bottom" 0.04, this means that the value will be in the left tail of the distribution and will be a negative value.

z= -1.75

Now using the formula of the distribution and the parameters of X you have to transform the Z-value into a value of X

z= (X-μ)/σ

z*σ = X-μ

(z*σ)+μ = X

X= (-1.75-0)/1= -1.75ºC

The value that separates the bottom 4% is -1.75ºC

I hope this helps!

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3 years ago

1. 4x + 3(x-9) = 19

Dmitry_Shevchenko [17]

1) 4x + 3(x-9) = 19

or, 4x + 3x - 27 = 19

or, 7x = 19+27

or, 7x = 46

or, x = 46/7

◆ x = 6.57

2) 2(x-4) + 5x = 3

or, 2x - 8 + 5x = 3

or, 7x = 3+8

or, x = 11/7

◆ x = 1.57

3) 60 = 8y - 3(y-10)

or, 60 = 8y - 3y + 30

or, 60 - 30 = 5y

or, y = 30/5

◆ y = 6

4) 40 + 3c = 3 + 9(c-2)

or, 40 + 3c = 3 + 9c - 18

or, 40 + 3c = 9c - 15

or, 9c - 3c = 40 + 15

or, 6c = 55

◆ c = 9.166

I hope you understand..

Thank you...♥♥

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2 years ago

Read 2 more answers

The area of a right triangle is given by the expression:

lorasvet [3.4K]

The expression that models the length of the second leg of the triangle is 2x - 3.

Recall:

The area of a triangle = $\frac{1}{2} bh$

Given:

Area of triangle = $\frac{1}{2} (6x^2 - 7x - 3)$

Length of one of the legs = 3x + 1

Therefore, it means that multiplying both legs should give us:

$6x^2 - 7x - 3$

To find the expression that models the other leg, divide $6x^2 - 7x - 3$ by 3x + 1:

Thus:

$\frac{6x^2 - 7x - 3}{3x - 1}$

Factorize the numerator

$\frac{6x^2 - 2x - 9x - 3}{3x - 1}\\\\\frac{2x(3x - 1) - 3(3x - 1)}{3x - 1}\\\\\frac{(2x- 3)(3x - 1)}{3x - 1}$

Simplify

$\frac{(2x- 3)(3x - 1)}{3x - 1} = 2x- 3$

Therefore, the expression that models the length of the second leg of the triangle is 2x - 3.

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1 year ago

A line passes through (2, –1) and (8, 4). a. Write an equation for the line in point-slope form. b. Rewrite the equation in stan

pentagon [3]

The point-slope form of a line is:

y-y1=m(x-x1), where m=slope and (x1,y1) is any point on the line

First we need to find the slope, which is (y2-y1)/(x2-x1)

m=(4--1)/(8-2)

m=5/6 and we can use either point, I'll use (8,4)

y-4=(5/6)(x-8)

That is your equation in point-slope form.

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y-4=(5/6)(x-8) we can perform the indicated multiplication on the right side

y-4=(5x-40)/6 multiply both sides by 6

6y-24=5x-40 add 24 to both sides

6y=5x-16 subtract 5x from both sides

-5x+6y=-16 and by convention, the standard equation of a line should be expressed with a positive coefficient for x, so multiply both sides by -1

5x-6y=16

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3 years ago