Which of the following is a pair of vertical angles ?

Mathematics

2 answers:

beks73 [17]3 years ago

6 0

Answer

∠AOB and ∠DOC are a pair of vertical angle

Step-by-step explanation

Given in the figure we have to choose the angle which are vertically opposite to each other.

The vertically opposite angles are the angles vertically opposite when two line cross each other.

Option A

∠AOB and∠DOC are vertically opposites to each other so they are a pair of vertical angle

Option B

∠AOB and∠EOA are not vertically opposite to each other so they are not a pair of vertical angle.

Option C

∠DOC and ∠EOB are not vertically opposite to each other so they are also not a pair of vertical angles .

Option D

∠EOB and∠EOA are also not vertically opposite to each other so they are also not a pair of vertical angle

Therefore, ∠AOB and ∠DOC are a pair of vertical angles

nikklg [1K]3 years ago

5 0

Vertical angles are the angles opposite each other when two lines cross, so
∠AOB and ∠DOC are vertical.

You might be interested in

Collect like terms x+x+x

Vlad [161]

The correct answer is 3x

3 0

3 years ago

Read 2 more answers

The change in water level of a lake is modeled by a polynomial function, W(x). Describe how to find the x-intercepts of W(x) and

Agata [3.3K]

First. Finding the x-intercepts of $W(x)$

Let $W(x)$ be the change in water level. So to find the x-intercepts of this function we can use The Rational Zero Test that states:

To find the zeros of the polynomial:

$f(x)=a_{n}x^{n}+a_{n-1}x^{n-1}+...+a_{2}x^{2}+a_{1}x+a_{0}$

We use the Trial-and-Error Method which states that a factor of the constant term:

$a_{0}$

can be a zero of a polynomial (the x-intercepts).

So let's use an example: Suppose you have the following polynomial:

$W(x)=x^{4}-x^{3}-7x^{2}+x+6$

where the constant term is $a_{0}=6$ . The possible zeros are the factors of this term, that is:

$1, -1, 2, -2, 3, -3, 6 \ and \ -6$ .

Thus:

 $W(1)=0 \\ W(-1)=0 \\ W(2)=-12 \\ W(-2)=0 \\ W(3)=0 \\ W(-3)=48 \\ W(6)=840 \\ W(-6)=1260$ 

From the foregoing, we can affirm that $1, -1, -2 \ and \ 3$ are zeros of the polynomial.

Second. Construction a rough graph of $W(x)$

Given that this is a polynomial, then the function is continuous. To graph it we set the roots on the coordinate system. We take the interval:

$[-2,-1]$

and compute $W(c)$ where $c$ is a real number between -2 and -1. If $W(c)>0$ , the curve start rising, if not, the curve start falling. For instance:

$If \ c=-\frac{3}{2} \\ \\ then \ w(-\frac{3}{2})=-2.81$

Therefore the curve start falling and it goes up and down until $x=3$ and from this point it rises without a bound as shown in the figure below